Consider a machine with a byte addressable main memory of 256 Kbytes which has 3

Question

Consider a machine with a byte addressable main memory of 256 Kbytes which has 32K total blocks. Assume a direct mapped cache consisting of 512 lines is used with this machine.
a) How is the memory address divided into tag, line number, and byte number?
b) Into what line would bytes with the each following addresses be stored?
00 0001 1011 1101 0001
00 0100 1110 0011 0011
00 1101 0100 1001 0001
00 1010 0011 0110 0101
c) Suppose the byte with address 00 0001 1001 1111 0010 is stored in the cache. What are the addresses of the other bytes stored along with it?
d) For the main memory address of 3AA9B, give the corresponding cache information (line, tag, word)
e) How many total bytes can be stored in this cache?
f) Why is the tag also stored in the cache?

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