I\'m having trouble with this one problem and I need some help. I\'m a beginner

Question

I'm having trouble with this one problem and I need some help. I'm a beginner at C++ so please go easy on me.

To make telephone numbers easier to remember, some companies use letters to show their telephone number. For example, using letters, the telephone number 438-5626 can be shown as GET LOAN. In some cases, to make a telephone number meaningful, companies might use more than seven letters. For example, 225-5466 can be displayed as CALL HOME, which uses eight letters. Write a program that prompts the user to enter a telephone number expressed in letters and outputs the corresponding telephone number in digits. If the user enters more than seven letters, then process only the first seven letters. Also output the

Explanation / Answer

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Program:

===================================================

#include<iostream>
#include<ctype.h>
#include<stdio.h>
using namespace std;
int main()
{
    char letter[10];
    int noOfLetters;
    char response[8];
    char ch;
    int c=0;
    while(1)
    {
        response[0]='';
        c=0;
        fflush(stdin);
        cout<<" Enter the phone letters: ";
        cin.getline(letter,10);
        noOfLetters=0;
        while(letter[noOfLetters]!='')
        {
            if(letter[noOfLetters]==' ')
            {
                noOfLetters++;
                continue;
            }
            char l=tolower(letter[noOfLetters]);
            switch(l)
            {
                case 'a':case 'b':case 'c':response[c]='2';c++;break;
                case 'd':case 'e':case 'f':response[c]='3';c++;break;
                case 'g':case 'h':case 'i':response[c]='4';c++;break;
                case 'j':case 'k':case 'l':response[c]='5';c++;break;
                case 'm':case 'n':case 'o':response[c]='6';c++;break;
                case 'p':case 'q':case 'r': case 's':response[c]='7';c++;break;
                case 't':case 'u':case 'v':response[c]='8';c++;break;
                case 'w':case 'x':case 'y': case 'z':response[c]='9';c++;break;
            }
            if(c==3)
            {
                response[c]='-';
                c++;
            }
            noOfLetters++;
        }
        cout<<" The number is: ";
        c=0;
        while(c<=7)
        {
            cout<<response[c];
            c++;
        }
        cout<<" Do you want to enter another phone number(letters)[y for yes]: ";
        cin>>ch;
        if(ch!='y')break;
    }
}

====================================================

Sample output:

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