Consider the following functions: int secret (int x) { int i, j; i = 2 * x; if (

Question

Consider the following functions:

int secret (int x)
{
int i, j;

i = 2 * x;

if (i > 10)
j = x / 2;
else
j = x / 3;

return j - 1;
}

int another(int a, int b)
{
int i, j;

j = 0;

for (i = a; i <= b; i++)
j = j + i;

return j;
}

Here are my answers based on the following program segments (Assume that x, y, and k are int variables.)

b. x = 5; y = 8;
cout << another(x, y) << endl;

ANSWER: 26

c. x = 10; k = secret(x);
cout << x << " " << k << " " << another(x, k) << endl;

ANSWER: 10 4 0

d. x = 5; x = 8;
cout << another(y, x) << endl;

ANSWER: 0

I have the answers, but for each of these, please explain to me how these are the answers so I can get a better understanding of this problem.

Explanation / Answer

For x=5,y=8 when you call the another function... for the first time it goes into the loop,for i=5,j=5+0=5. for the second time,for i=6,j=6+5=11 for the third time,for i=7,j=7+11=18 for fourth time,for i=8 and this is last time,j=8+18=26 And finally returns a value of 26 ////////////////////////////////////////////////////////// for secret(x) where x=10,i=2*10=20 (>10) =>j= x/2= 10/2 =5 return j-1 = 5-1 =4 you can find another(10,4).you would get a value of 0 //////////////////////////////////////////////////////////

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