Write a program in C++ that asks the user to enter some positive numbers until 0

Question

Write a program in C++ that asks the user to enter some positive numbers until 0 is entered. The program then reports the total of all even numbers entered. The users can enter as many numbers as they want. When negative numbers are entered, present a message to the user for the error but continue the program.

Following is the code I have gotten to be the closest. What am I doing wrong?

#include <iostream>
using namespace std;

int main()
{
int row = 1, //row counter
number, //holds number entered
total = 0; //sum of numbers


//Instructions
cout << "Please enter any positve, non-zero number. ";
cout << "Do this as many times you would like. ";
cout << "When done, enter a "0", to receive the total of all even numbers entered. ";
cout << " Please enter your number choice " << row << ": ";
cin >> number;

// Total will only add even numbers
if (number%2 == 0)
{
total += number;

}

while ( number != 0)
{
row ++;
total += number;
cout << "Please enter your number choice " << row << ": ";
cin >> number;

if ( number == 0)
{
cout << " The total sum of the even numbers entered is " << total << endl;

if ( number < 1)
{
cout << "Please enter a number 1 or greater: ";
cin >> number;
}
}
}

cout << " The total sum of the even numbers entered is " << total << endl;

return 0;
}

--sorry if it doesn't come out formatted..again--

Explanation / Answer

//C++ code
#include <iostream>
using namespace std;

int main()
{
int row = 1; //row counter number,
//holds number entered
int number;
int total = 0;
//sum of numbers
//Instructions
cout << "Please enter any positve, non-zero number. ";
cout << "Do this as many times you would like. ";
cout << "When done, enter a "0", to receive the total of all even numbers entered. ";
cout << " Please enter your number choice " << row << ": ";
cin >> number; // input number

while (true)
{
if (number%2 == 0 && number != 0)
{
total += number;
}
else if ( number == 0)
{
cout << " The total sum of the even numbers entered is " << total << endl;
break;
}

row ++;
//count number
// Display proper msg
if ( number < 0)
cout << "Please enter a number 1 or greater: ";
else
cout << "Please enter your number choice " << row << ": ";

cin >> number; // input number

  
}
return 0;
}

/*
output:

Please enter any positve, non-zero number.
Do this as many times you would like.
When done, enter a "0", to receive the total of all even numbers entered.

Please enter your number choice 1: 3
Please enter your number choice 2: 4
Please enter your number choice 3: 5
Please enter your number choice 4: 6
Please enter your number choice 5: 0

The total sum of the even numbers entered is 10

*/

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