Write a method writeSequence that accepts an integer n as a parameter and prints

Question

Write a method writeSequence that accepts an integer n as a parameter and prints a symmetric sequence of n numbers with descending integers ending in 1 followed by ascending integers beginning with 1, as in the table below: Call Output writeSequence(1); 1 writeSequence(2); 1 1 writeSequence(3); 2 1 2 writeSequence(4); 2 1 1 2 writeSequence(5); 3 2 1 2 3 writeSequence(6); 3 2 1 1 2 3 writeSequence(7); 4 3 2 1 2 3 4 writeSequence(8); 4 3 2 1 1 2 3 4 writeSequence(9); 5 4 3 2 1 2 3 4 5 writeSequence(10); 5 4 3 2 1 1 2 3 4 5 Notice that for odd numbers the sequence has a single 1 in the middle while for even values it has two 1s in the middle. Your method should throw an IllegalArgumentException if passed a value less than 1. A client using this method would have to call println to complete the line of output.

Explanation / Answer

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import java.util.*;
public class main
{
public static void main(String[] args)
{int n;
Scanner in = new Scanner(System.in);
System.out.print("Enter a number: ");
n=in.nextInt();
writeSequence(n);
}
public static void writeSequence(int n)
{int m;
if(n<1)
    throw new IllegalArgumentException();
else if(n==1)
    System.out.print(1);
else if(n==2)
    System.out.print("1 1");
else
    {m=(n+1)/2;
     System.out.print(m+" ");
     writeSequence(n-2);
     System.out.print(" "+m);
    }
}
}

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