Need help to modify my code so that it allows user to keep seaching values in ar

Question

Need help to modify my code so that it allows user to keep seaching values in array, then when user enters -1 the program ends this is

my code:

public class q3a{

public static void main(String[] args){

Scanner input = new Scanner(System.in);

Random randomGenerator = new Random();

System.out.println(" "+"Enter number of array elements: ");

int numTimes = input.nextInt();

int[] array1 = new int[numTimes];

System.out.println("Array Filled: ");

for(int i=0; i<array1.length; i++)

{ array1[i] = randomGenerator.nextInt(1000);

if(array1.length<16)

{ System.out.println(array1[i]);

}

else{System.out.println("Array too big to print. But it's filled. Take my word for it.");}}

q3a.bubbleSort(array1);

System.out.println(" "+"Enter a number to search for: ");

int value = input.nextInt();

if(q3a.binarySearch(array1, value)>0)

{

System.out.println("Searched "+q3a.binarySearch(array1, value)+" times.");

System.out.println("your value was found at position " +q3a.binarySearch(array1, value));

}

else{System.out.println("Value not found");} }

public static void bubbleSort(int[] array)

{

Arrays.sort(array);

System.out.println(" "+"Array Sorted:");

if(array.length<16)

{ for( int i=0; i<array.length; i++)

{ System.out.println(array[i]);

}

}

else{System.out.println("Array too big to print. But it's sorted. Take my word for it.");} }

public static int binarySearch(int[] array, int value)

{//Go through all of the array!

int count = 0;

for(int i = 0; i<array.length; i++)

{ count++;

if(array[i] == value)

{ return count;

}

}

return -1;}}

Proeper outputs

Explanation / Answer

import java.util.Arrays; import java.util.Random; import java.util.Scanner; public class q3a { public static void main(String[] args) { int value; Scanner input = new Scanner(System.in); Random randomGenerator = new Random(); System.out.println(" " + "Enter number of array elements: "); int numTimes = input.nextInt(); int[] array1 = new int[numTimes]; System.out.println("Array Filled: "); for (int i = 0; i 0) { System.out.println("Searched " + q3a.binarySearch(array1, value) + " times."); System.out.println("your value was found at position " + q3a.binarySearch(array1, value)); } else { System.out.println("Value not found"); } } }while(value!=-1); } public static void bubbleSort(int[] array) { Arrays.sort(array); System.out.println(" " + "Array Sorted:"); if (array.length < 16) { for (int i = 0; i

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