don\'t look for errors you just compile and run with the input 1 and 5 and expla

Question

don't look for errors you just compile and run with the input 1 and 5 and explain just how the compiler came with such results. #includevoidone(int * ptr_a, int * ptr_b); voidtwo(int * ptr_a, int b, int * ptr_c); voidthree(int a, int b, int c); int main() {int x = 0, y = 0, z = 0; printf("%d ,%d %d ", x, y, z); one(&x,&y); printf("%d ,%d %d ", x, y, z); two(&x,y,&z); printf("%d ,%d %d ", x, y, z); three(x, y, z); printf("%d ,%d %d ", x, y, z); two(&z,y,&x); printf("%d ,%d %d ", x, y, z);} void one (int * ptr_a, int * ptr_b) {printf("Enter a number: "); scanf("%d", ptr_a); //Notice: No '&' here printf("Enter another number: "); scanf("%d", ptr_b); //Notice: No '&' here} void two(int * ptr_a, int b, int * ptr_c){ b = b + 1; *ptr_c = *ptr_c - 1; *ptr_a = b + *ptr_c;} void three(int a, int b, int c) {a = b - c; b = c - a; c = a - b; printf("%d %d %d ", a, b, c); }

Explanation / Answer

output: 0 0 0 Enter a number: //give input as 1 here 1 Enter another number: //give input as 5 here 5 ......... similar output runs where it reads and prints as per code

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