A router with IP address 195.5.2.12 and Ethernet physical address AA: 25: AB: 1
ID: 3662898 • Letter: A
Question
A router with IP address 195.5.2.12 and Ethernet physical address AA: 25: AB: 1 F: 67: CD has received a packet for a destination with IP address 185.11.78.1 0. When the router checks its routing table, it nds out the packet should be delivered to a router with IP address 195.5.2.6 and Ethernet physical address AD:34:5D:4F:67:CD.
A. Show the entries in the ARP request packet sent by the router. Assume no subnetting.
B. Show the entries in the ARP packet sent in response to part a.
C. Encapsulate the packet made in part a in the data link layer. Fill in all the elds.
D. Encapsulate the packet made in part b in a data link frame. Fill in all the elds.
Explanation / Answer
Answer for Question 1 is:
OX 0001
OX 0800
OX 06 OX 04
OX 0001
OX 23:45:AB:4F:67:CD
Ox 7D:2D:17:0C
Ox 00:00:00:00:00:00
Ox 7D:0B:4E:0A
Answer for Question 2 is:
OX 0001
OX 0800
OX 06 OX 04
OX 0002
AA:BB:A2:4F:67:CD
Ox 7D:0B:4E:0A
OX 23:45:AB:4F:67:CD
Ox 7D:2D:17:0C
Answer for Question 3 is:
Answer for Question 4 is:
the data part will be raplaced by the ans of q.2 and the destination address will be: AA:BB:A2:4F:67:CD. And the source address field will be OX 23:45:AB:4F:67:CD.
OX 0001
OX 0800
OX 06 OX 04
OX 0001
OX 23:45:AB:4F:67:CD
Ox 7D:2D:17:0C
Ox 00:00:00:00:00:00
Ox 7D:0B:4E:0A
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