can someone please check my code because everytime i enter y it keeps prompting

ID: 3664220 • Letter: C

Question

can someone please check my code because everytime i enter y it keeps prompting me the message please enter your choice (y, n or q) instead of saying great choice goodbye for y

#include <stdio.h>

char GetInput(void){
/* while this is true.
It asks user to input a choice of y, n, or q.
If statement checks whether input is y, n, or q.
If user inputs a y, n, or q, then it would break out of while loop;
Otherwise it would continue to ask the user to print one of the three letters */
while(1){
char input;
printf("Please enter your choice (y for yes, n for no, q for quit) ");
scanf(" %c", &input);
if (input=='y' || input=='n' || input=='q'){
return input;
//break;
}
}
}
/* while this is true.
It asks user if they want an upgrade, keeps printing this message unless they input yes.
Once they enter yes the while loop breaks */

void SellUpgrade(int q_limit, int mbps, int mbps_increase, int price, int price_increase){
while(1){
printf("You are eligible for a limited time offer. You can get %d megabits per second for the low promotional rate of $%d a month. Act now while supplies last. ", mbps, price);
char x=GetInput(); // x is now getInput
int count=0; //sets initial count to 0
if(x=='y'){ //if user inputs y, then it prints the message
printf("Great choice. Goodbye. ", x);
break;
}
if(x=='n' || x=='q'){ // if user inputs n or q it continues to print the service upgrade message
return;
}
if (x=='q'){
count++; // increases count
if(count>q_limit){
return;
}
}
}
}
void PayBill(void){
printf("We already have your credit card information and have charged you.Thanks for being a loyal customer! ");
}

int main (){
int choice; // user has option to choose 1-4

printf("Welcome to Cablecom! Please make a choice from the following options: "); //opening menu

printf("1) Change your password ");

printf("2) Cancel your service ");

printf("3) Schedule a service call ");

printf("4) Pay your bill ");

scanf("%d", &choice);

if (choice!=1 && choice!=2 && choice!=3 && choice!=4){ // if choice is not between 1 and 4

printf("Please enter a number between 1 and 4. "); // prints the statement if choice is not between 1 and 4

scanf("%d", &choice); //user inputs a choice and feeds it into choice
}
else if (choice==1){
SellUpgrade(2, 10, 1, 50, 1);
}

else if (choice==2){
SellUpgrade(5, 100, 10, 80, 20);
}

else if (choice==3){
SellUpgrade(5, 40, 5, 60, 10);
}

else if (choice==4){
PayBill();
}

return 0;
}

You work for a cable company and are designing a software system to automate the customer service system. Your system is archaic, so you can only read in the inputs 1 through4, y n and from your user (the current customer) When your program begins, display the following menu to the user: [prompt]$ ./customer_experience Welcome to CableCom! Please make a choice from the following options: 1) Change your password 2) Cancel your service 3) Schedule a service call 4) Pay your bill For simplicity (to avoid this bug) assume the user always enters a number. If the user enters an incorrect number at the start of the program, print Please enter a numberbetween 1 and 4. and use scanf to obtain another input. WARNING: On the CSIF computers, if you type 3 and then hit enter, there are actually two inputs in the stdin buffer, not one. The buffer contains the character3, and the characterin, (a newline). You must call getchar to clear the buffer.

Explanation / Answer

I have fixed the issues with your code and marked the changes I have made in bold.I have explained the changes but still if you have any confusion then comment on the answer.

#include <stdio.h>
char GetInput(void){
   /* while this is true.
   It asks user to input a choice of y, n, or q.
   If statement checks whether input is y, n, or q.
   If user inputs a y, n, or q, then it would break out of while loop;
   Otherwise it would continue to ask the user to print one of the three letters */
   while (1){
       char input;
       printf("Please enter your choice (y for yes, n for no, q for quit) ");
       scanf(" %c", &input);
       if (input == 'y' || input == 'n' || input == 'q'){
           return input;
           //break;
       }
   }
}
/* while this is true.
It asks user if they want an upgrade, keeps printing this message unless they input yes.
Once they enter yes the while loop breaks */

void SellUpgrade(int q_limit, int mbps, int mbps_increase, int price, int price_increase){

//moved count out of the loop otherwise everytime you press q and go into while it will become 0,that is why it was //not coming out of loop after pressing q twice in option 1.

int count = 0; //sets initial count to 0

   while (1){
       printf("You are eligible for a limited time offer. You can get %d megabits per second for the low promotional rate of $%d a month. Act now while supplies last. ", mbps, price);
       char x = GetInput(); // x is now getInput
       if (x == 'y'){ //if user inputs y, then it prints the message
           printf("Great choice. Goodbye. ", x);
           break;
       }

//moved this if condition up because we should first check for count of q input and then process it in next if.
       if (x == 'q'){
           count++; // increases count
           if (count >= q_limit){
               return;
           }
       }

       if (x == 'n' || x == 'q'){// if user inputs n or q it continues to print the service upgrade message
           mbps += mbps_increase;
           price += price_increase;

//replaced the return statement with continue because we don't want to break out of the while loop we wan't //to take next input with new service upgrade message with new values of mbps and price.
           continue;
       }
   }
}
void PayBill(void){
   printf("We already have your credit card information and have charged you.Thanks for being a loyal customer! ");
}
int main(){
   int choice; // user has option to choose 1-4

printf("Welcome to Cablecom! Please make a choice from the following options: "); //opening menu

printf("1) Change your password ");

printf("2) Cancel your service ");

printf("3) Schedule a service call ");

printf("4) Pay your bill ");

scanf("%d", &choice);

if (choice != 1 && choice != 2 && choice != 3 && choice != 4){ // if choice is not between 1 and 4

printf("Please enter a number between 1 and 4. "); // prints the statement if choice is not between 1 and 4

       scanf("%d", &choice); //user inputs a choice and feeds it into choice
   }
   else if (choice == 1){
       SellUpgrade(2, 10, 1, 50, 1);
   }

   else if (choice == 2){
       SellUpgrade(5, 100, 10, 80, 20);
   }

   else if (choice == 3){
       SellUpgrade(5, 40, 5, 60, 10);
   }

   else if (choice == 4){
       PayBill();
   }

return 0;
}

Sample output for option 1 with q pressed twice

Welcome to Cablecom! Please make a choice from the following options:
1) Change your password
2) Cancel your service
3) Schedule a service call
4) Pay your bill
1
You are eligible for a limited time offer. You can get 10 megabits per second fo
r the low promotional rate of $50 a month. Act now while supplies last.
Please enter your choice (y for yes, n for no, q for quit)
q
You are eligible for a limited time offer. You can get 11 megabits per second fo
r the low promotional rate of $51 a month. Act now while supplies last.
Please enter your choice (y for yes, n for no, q for quit)
q
Press any key to continue . . .

sample output for option 1 with input y

Navigate

can someone please check my answers 7. (5 pts) What elimination product is forme

can someone please code this simple background subtraction but with height and w

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.

can someone please check my code because everytime i enter y it keeps prompting

Question

Explanation / Answer

Related Questions

Navigate