Assembly language 3. What will be the hexadecimal value of the destination opera
ID: 3665184 • Letter: A
Question
Assembly language
3. What will be the hexadecimal value of the destination operand after each of the following statements has executed? If any instruction is illegal, write the word ILLEGAL as the answer. var1, var2 and count are 16 bit variables. All the numbers are in hexadecimal After Before Instruction mov ahab AX-1A5, BX-4F5B AX mov offset Var2,03h Var2 9876 Var2 DX-8F1A, count-004C DX- mov dl,count, mov dx,34h EDX EDX-8CE155AA EDI mov edi,0A0000000h EDI 06E948CD DX mov dx.cx DX-A000, CX-B800 mov bluax. BL- BX-004C, AX-4000 var -0025, BX-A000 VartE mov var1,bx mov var1,var2 var1-0501, var 2-4050 var mov, var ebx var1 1225, EBX-8899 varExplanation / Answer
instruction before After
mov ah,bl AX=1A5,BX=4F5B AX=5BA5 (lower byte of B to higherbyte of A)
mov offset Var2,03h var2=9876 var2=03h
mov dl,count DX=8F1A,count=004C DX=8F4Ch( lower byte of count to lower byte of dX
mov dx,34h EDx=8CE155AA EDX=00000034H
mov edi,0A0000000h EDI=06E948CD EDI= A0000000H
mov dx,cx DX=A000,CX=B800 DX=B800h
mov bl,ax BX=004C,AX=4000 BL=0000h
mov var1,bx var1=0025,bX=A000 var1=A000h
mov var1,var2 var1=0501h , var2=4050 var1=4050h
mov var1,[ebx] var1=1225, EBX=8899 var1=00008899h
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