Code a program to calculate the time in minutes for someone to cut a yard. Input

Question

Code a program to calculate the time in minutes for someone to cut a yard. Input the length and width of the yard in feet. Input the length and width of the house in feet. Subtract the area of the house from the area of the yard to determine the amount of grass to be cut. Using 2 square feet per second as the rate at which you can cut the grass (set this up as a constant), determine how long it will take someone to mow the lawn, in minutes.

The program should print:

         Length and width of yard

         Length and width of house

         Area to be cut in square feet

         Time to mow the yard in minutes

Input data: (run three times)

         Yard - 1500 X 1600 feet

         House - 500 X 700 feet

         Yard – 4850 X 6000

         House – 1000 X 2000

Explanation / Answer

#include<stdlib.h>
#include<stdio.h>
#include<conio.h>
long Area_Yard=0,Area_House=0;
int Lengthofyard=0,Widthofyard=0,HouseLength=0,HouseWidth=0;
long GroundArea=0;
int TimeRequiredtocut=0;
int GrassCuttingRate=2;
void main()
{
char input[256];
clrscr();
printf("GRASS CUTTER PROGRAM");
printf("please Enter the Length of Yard ");
gets(input);
Lengthofyard= atoi(input);
printf("please Enter the Width of Yard ");
         gets(input);
Widthofyard=atoi(input);
    printf("please Enter the Length of House ");
         gets(input);
HouseLength=atoi(input);
   printf("please Enter the Width of House ");
         gets(input);
HouseWidth=atoi(input);
Area_House=HouseWidth *HouseLength ;
Area_Yard=Widthofyard* Lengthofyard;
GroundArea=Area_Yard-Area_House;
   TimeRequiredtocut=GroundArea/GrassCuttingRate;
printf("%s%d","Grass Area is ",GroundArea);
printf("%s%d seconds"," time Required To cut it in seconds is " ,TimeRequiredtocut);
getchar();
}

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