Write a C++ program that asks the user to enter the numbers 1 to 16 (in any orde

Question

Write a C++ program that asks the user to enter the numbers 1 to 16 (in any order) and then displays the numbers in a 4 x 4 aligned arrangement, followed by the sums of the rows, columns, and diagonals. A session of the program will look like

Enter the numbers from 1 to 16 in any order:

16 3 2 13 5 10 11 8 9 6 7 12 4 15 14 1

The 4 x 4 arrangement is

16 3 2 13

5 10 11 8

9 6 7 12

4 15 14 1

Row sums: 34 34 34 34

Column sums 34 34 34 34

Diagonal sums: 34 34

Note: If the row, column, and diagonal sums are all the same, the numbers are said to form a magic square.

Hint: use setw function to specify field width. Look online to find the library that is required for this function.

Explanation / Answer

#include <iostream>
#include <iomanip>

using namespace std;
void magic(int a[4][4])//To find whether the values form magic square or not
{
//For diagonal elements
int sum = 0,row,column,size=4,flag=0;

for ( row = 0; row < size; row++) {
for (column = 0; column < size; column++) {
if (row == column)
sum = sum + a[row][column];
}
}

//For Rows
for (row = 0; row < size; row++) {
int sum1 = 0;
for (column = 0; column < size; column++) {
sum1 = sum1 + a[row][column];
}
if (sum == sum1)
flag = 1;
else {
flag = 0;
break;
}
}

//For Columns
for (row = 0; row < size; row++) {
int sum2 = 0;
for (column = 0; column < size; column++) {
sum2 = sum2 + a[column][row];
}
if (sum == sum2)
flag = 1;
else {
flag = 0;
break;
}
}

if (flag == 1)
cout<<" Magic square";
else
cout<<" No Magic square";


}

int main()
{
int a[4][4],b[16],i,j,k,sum;
cout<<" Enter the 16 values between 1-16 in any order ";
  
for(i=0;i<4;i++)
{
for(j=0;j<4;j++)
{
cin>>a[i][j];
}
}
for(i=0;i<4;i++)
{
for(j=0;j<4;j++)
{
cout<<setw(4)<<a[i][j];
}
cout<<" ";
}
for(i=0; i<4; i++)
{
sum = 0;
for(j=0; j<4; j++)
{
sum += a[i][j];
}
  
cout<<" Sum of elements of Row "<<i+1<< "="<<sum ;
}
for(i=0; i<4; i++)
{
sum = 0;
for(j=0; j<4; j++)
{
sum += a[j][i];
}
  
cout<<" Sum of elements of column "<<i+1<< "="<<sum ;
}
sum = 0;
int sum1=0;
for (i = 0; i < 4; ++i)
{
sum = sum + a[i][i];
sum1 = sum1+ a[i][4 - i - 1];
}
cout<<" The sum of the main diagonal elements is =" <<sum;
cout<<" The sum of the off diagonal elemets is ="<< sum1;
magic(a);
}

Magic function is created for find wheather the given values form magic square or not

If you have any doubts regarding this program i will clarify to you

Thank u...

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