Write a C++ program which does following: Simulate an array by a linear linked l

Question

Write a C++ program which does following:

Simulate an array by a linear linked list:

Let A be an array that stores up to n (n=100 here) integers. We will use a linked list L to represent A. Your task is to write a C++ program that simulates operations on A by using L, and outputs results.

The following is an example snapshot of L and A at some given time:

int A[8]; A[1]=5; A[3]=2; A[4]=1; A[6]=7

/* node definitions for L */

struct node {

   int index;

   int data;

   node* next;

};

typedef node *link;

AGAIN ASSUME THAT THE LIST DOES NOT CONTAIN MORE THAN 100 ELEMENTS

Do the following operations on L (the operations are defined on A; we need to perform equivalent operations on L):

HERE WE IMAGINE OPERATIONS ON A, BUT ACTUALLY DO THEM ON L, AND ALL ELEMENTS IN THE LIST ARE DISTINCT

A i x : Set A[i]=x

T : Output all data values in A (only the final assigned value, other parts are not used in A)

R: Resets A. All elements are reset meaning that there is no data in A.

I: Increment by 1 all elements of A.

Sample input/output:

A 1 5

A 3 4

A 4 1

A 6 7

A 3 2

I

T

index: 1 value: 6

index: 3 value: 3

index: 4 value: 2

index: 6 value: 8

R

A has been reset

T

No data in A now

A 1 5

T

index: 1 value: 5

Explanation / Answer

// A program to simulate a linear linked list using an array /*********************************************************************************************************************/ #include #include using namespace std; struct node { int data; int prev; int next; // Constructor: node() { data = -1; prev = -1; next = -1; } }; node A[100]; // Array of nodes used to simulate the linked list int slot = 1; // Array index of the next free space (beginning from index 1 initially) int head = -1; // Array index of the starting element in the list (-1 implies no entries yet) int tail = -1; // Array index of the tail in the list int elements = 0; // Number of elements in the list // Function prototypes: void insert(int); void insertAfter(int,int); void deleteElement(int); void reverse(); void print(); int findIndex(int); int main() { int a, b; char c; cout > c; switch(c) { case 'A': cin >> a; insert(a); break; case 'I': cin >> a >> b; insertAfter(a,b); break; case 'D': cin >> a; deleteElement(a); break; case 'R': reverse(); cout

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