Using the Arduino IDE, write code to convert any base-10 integer to its base-2 e

Question

Using the Arduino IDE, write code to convert any base-10 integer to its base-2 equivalent. Your code should define the base-10 value as a variable, and print out to the serial port the final base-2 value. While there are many different approaches you could take to this problem, here are some suggestions and hints:

• The modulo operator (%) can be used to find the remainder of a division operation.

• Division using two integers will result in an integer that represents the quotient of the division operation (the remainder will be dropped).

• For this problem it is convenient to represent the binary number as an alphanumeric string, rather than a number. In languages like C, strings are just arrays of single characters, and are difficult to manipulate. An alternative is to use a String object (note the capital ‘S’ in String). It is quite easy to add new characters (in our case ‘1’ or ‘0’) to a String object using the ‘+’ operator (e.g. see https://www.arduino.cc/en/Tutorial/StringAdditionOperator).

Explanation / Answer

#include<stdio.h>
int main(){

long int decimalNumber,remainder,quotient;
int binaryNumber[100],i=1,j;
printf("Enter any decimal number: ");

scanf("%ld",&decimalNumber);

quotient = decimalNumber;
while(quotient!=0){

binaryNumber[i++]= quotient % 2;

quotient = quotient / 2;
}
printf("Equivalent binary value of decimal number %d: ",decimalNumber);

for(j = i -1 ;j> 0;j--)

printf("%d",binaryNumber[j]);

return 0;
}

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