Write a method in C++ that: generates a stream of random integers between 0 and

Question

Write a method in C++ that:

generates a stream of random integers between 0 and 80

for each random number, prints that many asterisks in a line

keeps generating random numbers until either a number divisible by 11 is generated or a total of 50 numbers has been generated

For example, suppose the numbers 7, 17, 21, 5 and 33 were generated. Then the output would be as follows:

Set up your main program to call this method 3 times. Before the method gets called, give a number of which call you're on, e.g. "Call 1:" and then the method's output. After each call, give a blank line.

Explanation / Answer

#include<iostream>
#include<cstdlib>
#include<cstring>
#include<string>
using namespace std;
void display()
{
int arr[50];
int count;
int i=0;
int k=0;
int flag=0;
int temp=0;
do
{
flag=0;
temp=rand()%80;;
arr[i]=temp;
i++;
if(temp%11==0)
{
flag=1;
}
}while(flag!=1&&i<50);
   
   
string str="";
for(k=0;k<i-1;k++)
{
str="";
while(arr[k]--)
{
str=str.append("*");
}
cout<<str<<" ";
}



}
int main()
{
display();
display();
display();

return 0;
}

-------------------------------------

output

This is divisible by 11
***********************
******
*********************************************************
***********************************
This is divisible by 11
***************
**************************
************
*********
*************************************************************
******************************************
***************************
**************************************************
***********************************************************
***
******
************************************************************
This is divisible by 11
****************************************************
********************************************************
shekhar@shekhar-HP:~/Desktop/chegg/CS/cpp$

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