Assume the availability of a method named makeLine that can be passed a non-nega

Question

Assume the availability of a method  named  makeLine that can be passed a non-negative integer  n and a character  c and return a String consisting of n identical characters that are all equal to c. Write a method  named  printTrianglethat receives two integer  parameters  n and k. If n is negative the method does nothing. If n happens to be an even number, its value is raised to the next odd number (e.g. 4-->5). Then, when k has the value zero, the method prints a SYMMETRIC triangle of O's (the capital letter O) as follows: first a line of n O, followed by a line of n-2 O's (indented by one space), and then a line of n-4 O's (indented by two spaces), and so on. For example, if the method received 5,0 (or 4,0) it would print:
OOOOO
  OOO
     O

Note: in the above output , the first line contains 0 spaces before the first O, the next line 1 space, and so on.

Note: These instructions state what the method does when k is zero, but it is up to you, the programmer, to determine what it does when k is not zero and use it for your advantage.

The method must not use a loop of any kind (for, while, do-while) to accomplish its job. The method should invoke makeLine to accomplish the task of creating Strings of varying lengths.

Explanation / Answer

#include<iostream.h>
#include<conio.h>

void makeLine(int n, char c)
{
   for(int i=0;i<n;i++)
   {
       cout<<c;
   }
   getch();
}

void printTriangle(int n, int k)
{
   if(n<0)
   {
   }
   else if(n%2==0)
   {
       n=n+1;
   }

   if(k==0)
   {
       int s=0,i,j,z;
       for(z=n;z>=1;z=z-2)
       {
           for(i=1;i<=s;i++)
           {
               cout<<" ";
           }
           for(j=1;j<=z;j++)
           {
               cout<<"O";
           }
           s++;
           cout<<endl;
       }
   }
}

void main()
{
   makeLine(10,'a');
   printTriangle(4,0);
   getch();
}

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