Java: Chapter 4 Number 11: 11. Write a method called longestName that accepts a

Question

Java: Chapter 4 Number 11:

11. Write a method called longestName that accepts a Scanner for the console and an integer n as parameters and IL Write a method calld longestHame tht acepts a scanner for the console and an ineger as araners and prompts for n names, then prints the longest name (the name that contains the most characters) in the format shown below, which might result from a call of longestName (console, 4): name #1? Roy name #2? DANE name #3? sTeFaNE name #4? Mariana Stefanie's name is longest

Explanation / Answer

Answer:

NameLength.java

import java.util.*;

import java.io.*;

public class NameLength {
public static void main(String[] args) {
Scanner read=new Scanner(System.in);
   System.out.println("Enter number of names to be accepted:");
   int NUM_NAMES = read.nextInt();
   Scanner console=new Scanner(System.in);
   //System.out.println("Please Enter The Names: ");
   longestName(console,NUM_NAMES);
   
}
   public static void longestName(Scanner console,int NUM_NAMES)
   {
       String longest_string = "";

    for(int i=0; i<NUM_NAMES; i++){
System.out.print("name # "+(i+1)+": ");
String str=console.nextLine();
if( str.length() > longest_string.length() )
{
longest_string = str;
}
}
System.out.println(longest_string+" 's name is longest");

   }
}

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