Write it in program C The town of Rien. Ohio currently has a population 9.870. D

Question

Write it in program C The town of Rien. Ohio currently has a population 9.870. Due to the recent boom in craft breweries in the town, the population has been growing at a rate of 10% per year. The city fathers are concerned about what will happen when the town reaches 30.000 people and the strain that this type of population will put on the public utilities etc. You are to write a program that uses a loop to compute in what year Rien will reach 30.000 people. But you immediately realize that if you made the program more general, allowing a community to enter their current population and their Target" population, they could also use this software. So you are to have the user enter the current year, the current population and target population. It will then display the population for each year, terminating when the target population has been reached or exceeded. (Note that population growth is like compound interest, the "interest" is computed as a percentage of the larger population at the end of each year: pop = pop + pop*growth_r;) It looks something like this: Your program should have a comment block at the top of the program which includes your name and some information about the program. It should work for any year or population

Explanation / Answer

population.c

#include <stdio.h>

int main()
{
   int year;
   long population,targetPopulation;
   double growthRate;

   printf("Welcome to Population Projector ");

   printf(" Begin by entering the current year => ");
   scanf("%d",&year);

   printf(" Now enter your towns's current population => ");
   scanf("%ld",&population);

   printf(" Enter the expected population growth as a percentage => ");
   scanf("%lf",&growthRate);

   printf(" Now enter the target population => ");
   scanf("%ld",&targetPopulation);
   printf(" ");
   while(population<=targetPopulation)
   {
       printf("%d %ld ",year,population);
       population=population+population*growthRate/100;
       year++;

       if(population>=targetPopulation)
       {
           break;
       }
   }
  
   printf("In the year %d you will exceed your target of %ld with a population of %ld",year,targetPopulation,population);
  
   return 0;
}

sample output

Welcome to Population Projector

Begin by entering the current year => 2016

Now enter your towns's current population => 10000

Enter the expected population growth as a percentage => 12

Now enter the target population => 48000

2016 10000

2017 11200

2018 12544

2019 14049

2020 15734

2021 17622

2022 19736

2023 22104

2024 24756

2025 27726

2026 31053

2027 34779

2028 38952

2029 43626

In the year 2030 you will exceed your target of 48000 with a population of 48861

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