Develop a C program that defines two functions, one to compute the area of a tri

Question

Develop a C program that defines two functions, one to compute the area of a triangle, the other function to compute the circumference of a triangle. The program must include the function prototypes and call these functions from main.

Develop a computational model (with a C program) that computes the slope of a line between two points in a plane: P1 with coordinates (x1 , y1 ), and P2 with coordinates (x2,y2). The program should include two functions: main and slopef. The parameters of the second function (slopef) are the coordinates of the points in a plane. Use the coordinate values: (0,3/2) and (2,0).

Explanation / Answer

C Program to find the area of traingle and circumference of traingle

#include<stdio.h>
#include<math.h>

double area_of_triangle(double, double, double);
double circumference_of_triangle(double, double, double);
double area_of_triangle( double a, double b, double c )
{
double s, area;

s = (a+b+c)/2;

area = sqrt(s*(s-a)*(s-b)*(s-c));

return area;
}
double circumference_triangle( double a, double b, double c )
{
double circum;

circum = a+b+c;

return circum;
}

main()
{
double a, b, c,area,circumference;

printf("Enter the sides of triangle :");

scanf("%lf%lf%lf",&a,&b,&c);


area = area_of_triangle(a, b, c);   
circumference = circumference_triangle(a, b, c);


printf("Area of triangle = %.2lf ", area);

printf("Circumference of triangle = %.2lf ", circumference);

return 0;
}

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C Program to find the Slope of the line between two points (x1,y1) and (x2,y2)

#include <stdio.h>
#include <math.h>

float slope(float x1,float x2,float y1,float y2)
{
   float slo,dx,dy;
   dx = x2 - x1;
   dy=y2-y1;
slo=dy / dx;
return slo;
}
int main( void)
{
float x1,x2 ,y1 , y2 ,m;

printf("Enter the two points scale on the two axis X and Y : ") ;
scanf("%f%f%f%f", & x1, & x2 , & y1 , & y2 ) ;
m=slope(x1 , x2 , y1 , y2);

printf("Slope of the line with end points (%f, %f) and (%f, %f) = %f", x1, y1, x2, y2, m);

return 0;
}

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