Using the information that \'A\' - \'A\' gives 0, \'B\' - \'A\' gives 1... \'Z\'

Question

Using the information that 'A' - 'A' gives 0, 'B' - 'A' gives 1... 'Z' - 'A' gives 25 a. Declare an array of 25 integers. b. Initialize all the elements to 0. c. Then using code below as a starter, go thru the two dimensional array of random characters *nd count how many of each letter you find. You do not need any if or switch statements only use 'A' - character as the index to the array of integers. d. Then print the array of counts with labels like A: 3 If there were 3 As in the array. char y[10][25]; int row, col, I, counts[25]; fillArray(y);

Explanation / Answer

char y[10][25];
int row,col,i,counts[25];
fillArray(y);
//tracing through 2d array
for(row=0;row<10;row++)
{
   for(col=0;col<25;col++)
   {
   //finding ascii value of character
       i = (int)y[row][col] ;
   //as ascii values start from 65 substract with 65 so that a has value 0
       i=i-65;
   //store the number of times every character repeats
       counts[i]++;
   }
}
for(i=0;i<25;i++)
//print the character and its count
   printf("%c : %d ",i+65,counts[i]);

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