Consider a VoIP case. The sender generates bytes at a rate of 6,000 bytes per se

Question

Consider a VoIP case. The sender generates bytes at a rate of 6,000 bytes per second; every 50 msecs the sender gathers these bytes into a chunk

a). What is the number of bytes in a chunk?

b) Let h be the total number of header bytes added to each chunk, including UDP and IP header. Assuming an IP datagram is emitted every 50 msecs, find the transmission rate in bits per second for the datagrams generated by the sender.

c) What is a typical value of h when RTP is used? (Hint: in addition to UDP and IP header, what header RTP will add, and how long is it)

Explanation / Answer

a) 50 ms * 6000 bytes /sec = 300 bytes
b) ( 300 + h) bytes / datagrams
      1sec / 50 ms = 20 datagrams /sec
      Transmission rate = 20 (300 + h) bytes /sec
                                   = ( 0.05 / 20) (300 + h) bytes/sec
                                   = 0.0025 (300 + h) bytes/sec
                                    = 2.5 (300 + h) kbps
                                   = (750 + 2.5h) kbps

c) IP header: 20 bytes
     UDP header: 8 bytes
     RTP header: 12 bytes
   h = 40 bytes

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