Two card an dealt to you out of a deck of 52 cards Will is the probability of ea

Question

Two card an dealt to you out of a deck of 52 cards Will is the probability of each Please match the following with the best response: Any two cards 48/52 x 47/51 A 10 and a 5 52/52 x 12/51 A per of 6s 52/52 x 51/51 The 8 of spades and the 6 of spades 8/52 x 3/51 A pair of 8s or 6s 52/52 x 8/51 The ace of spades of one of the two cards 8/52 x 4/51 The ace of spades is one of the two cards 2/52 x 1/51 Does not include a2 4/52 x 3/51 The 2 of spades and the 2 of spades (1/52 x 51/51) + (51/51 x 1/51) two suited or not-suited connected cards (remember that an ace can be high or low) If you need to justify an answer do it here

Explanation / Answer

1)

Any two cards probability is 52/52*51/51

option C

2)

A 10 and a 5

so there are 4 10's and 4 5's

probablity of picking one 10 and one 5 is

(4C1*4C1)/52C2

=32/51*52

option F

3)

A Pair of 6's

there are 4 6's in the deck so

=4C2/52C2

=12/51*52

option H

4)

8 of spades and 6 of spades

so probability is 1/52C2

Option G

5.

A pair of 8''s or 6's

this involves two scenarios one with 8's and other with 6's

probability=4C2/52C2 + 4C2/52C2

=24/51*52

Option D

6.

Ace of spades is one of the card so other card can be anything and number of ways of selecting that are 51

so probability is

=51/52C2

=2/52

Option I

7.)

Two cards of same suit

First ways to select suit is 4

Ways to select card of that suit 13C2

probability=

=4*13C2/52C2

=12/51

Option B

8).

Does not include a 2,selct from other 48 cards

=48C2/52C2

=47*48/51*52

Option A

9)

The 2 of spades and the 2 of spades

there is only one 2 of spades so probability is

=1/52*0/51

=0

Option J

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