Lecture 7 example1: #include<iostream> using namespace std; int main() { const i

Question

Lecture 7 example1:

#include<iostream>

using namespace std;

int main()

{

   const int n = 20;

   int i, j, x, y;

   char numbers[n] = "2434:342";

   char num[n];

   // Find Colon Position

   for(i = 0, j = 0; i < n && numbers[i] != ''; i++, j++)

   {

       // Copy Contents from one string to another

       num[j] = numbers[i];

       if(numbers[i] == ':')

       {

           // Make valid string, convert first number to integer

           num[j] = '';  

           x = atoi(num);

           j = -1;       // Reset index

       }

   }

   // Add String Terminator to make it a valid string

   num[j] = '';

   y = atoi(num);

   // Display Results

   cout << "x = " << x << ", " << "y = " << y << endl;

   return 0;

}

1. In this exercise you need to process a raw data and extract some information. Your raw data is a string literal with following content: Name:grade1,grade2 For example John:78,64 You need to extract the name and the grades, and print them in the console, also you are required to calculate the average of these 2 grades and print it too. Note: You are required to use C-style String Hint: You can check the lec 7 example 1.

Explanation / Answer

#include <iostream>
#include <stdlib.h>
#include <stdio.h>

using namespace std;


int main()
{
const int n = 100;
int i, j, first, second;
char data[n] = "John:78,64";
char num[n];

// Find Colon Position
for(i = 0; data[i] != ':'; i++)
num[i] = data[i];

num[i] = '';

cout<<"Name of the person is "<<num;

for(++i, j=0; data[i] != ','; j++, i++)
num[j] = data[i];

first = atoi(num);

for(++i, j=0; data[i] != ''; j++, i++)
num[j] = data[i];

second = atoi(num);

cout<<" Grade 1 is "<<first<<endl;
cout<<"Grade 2 is "<<second<<endl;
cout<<"Average is "<<(first+second)/2.0<<endl;
return 0;
}

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