Program Specifications: (2) Get from the user the number of times they want to r

Question

Program Specifications:
(2) Get from the user the number of times they want to roll a pair of dice.

(3) Generate pseudorandom numbers to represent a roll of 2 dice. Be sure to call the rand function for each die value. Each die will have 6 sides, numbered 1 to 6. A single score is the sum of these 2 dice.

(4) Now make a loop that will do this the amount of times the user asked for. What type of loop is most appropriate?

(5) Count how many times a score of 2 is rolled, a score of 3 is rolled, a score of 4 is rolled, and so on up to a roll of 12. Output these counts. Example table output:

(6) Now calculate and output the probability of rolling each score (the percentage of times each score was rolled). Be sure you are using floating-point division and not integer division here. Example output: (Do not format output.)

This is what we are given to start:

#include
//Include library necessary for rand function

using namespace std;

int main() {
srand(1111); // Do not change the seed value.

// Declare all necessary variables


cout << "Enter number of times you want to roll a pair of dice: ";
// Get user input
cout << endl;

// Calculate roll counts

cout << "# of times each score was rolled" << endl;
// Output roll count table

cout << endl;   
cout << "Probability of rolling each possible score" << endl;
// Output percentage table

return 0;
}

Explanation / Answer

# include <stdio.h>

#include<stdlib.h>

#include<math.h>

using namespace std;

int main() {

Srand(1111);

int c1=0,c2=0,c3=0,c4=0,c5=0,c6=0;

int f1=0,f2=0,f3=0,f4=0,f5=0,f6=0;

int n; int sum =0; int count =0;

int face; int face 1;

cout<< “Enter no of times you want to roll a pair of dice:”;

cin>>n;

cout<,end1;

for(int i=1;i<=n;i++) {  

face = 1 + rand() %6;

face1 = 1 + rand() %6;

switch(face) {

case 1: ++c1; break;

case 2: ++c2; break;

case 3: ++c3; break;

case 4: ++c4; break;

case 5: ++c5; break;

case 6: ++c6; break;   }

switch(face1) {

case 1: ++f1; break;

case 2: ++f2; break;

case 3: ++f3; break;

case 4: ++f4; break;

case 5: ++f5; break;

case 6: ++f6; break;   }

switch(face) {

case 1: sum = c1+f1; break;

case 2: sum = c2+f2;break;

case3 : sum = c3 + f3;break;

case4: sum = c4+f4; break;

case5:sum =c5+f5; break;

case 6: sum = c6+f6; break; }

if(sum == 2)   count ++;

else if(sum == 3) count++;

else if(sum == 4) count++;

else if(sum == 5) count++;

else if(sum == 6) count++;

else if(sum == 7) count++;

else if(sum == 8) count++;

else if(sum == 9) count++;

else if(sum == 10) count++;

else if(sum == 11) count++;

else if(sum == 12) count++;

}

cout << " No of times each score was rolled" << endl;

for(int i=2;i<=12;i++ {

cout << i <<”%13d ” << count; }

cout << endl;  

cout << "Probability of rolling each possible score" << endl;

for(int i=2;i<=12;i++ {

float p =10 % * count;

cout<< i << “%f” << p; }

return 0;

}

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