Java Project Concepts tested by this program: Variables Input/output Loops Condi

Question

Java Project

Concepts tested by this program:

Variables

Input/output

Loops

Conditional Statements

Methods

Arrays

Multi-Dimensional Arrays

Classes

Objects

Program: The Location class

Problem Description:

**9.13 (The Location class) Design a class named Location for locating a maximal value and its location in a two-dimensional array. The class contains public data fields row, column, and maxValue that store the maximal value and its indices in a two-dimensional array with row and column as int types and maxValue as a double type.

Write the following method that returns the location of the largest element in a two-dimensional array:

public static Location locateLargest(double[][] a)

The return value is an instance of Location. Write a test program that prompts the user to enter a two-dimensional array and displays the location of the largest element in the array.

Here is a sample run:

Enter the number of rows and columns in the array: 3 4

Enter the array:

23.5 35 2 10

4.5 3 45 3.5

35 44 5.5 9.6

The location of the largest element is 45 at (1, 2)     

Coding:

Name your program

TestLocation.java

Location.java

Explanation / Answer

Location.java

public class Location {

public int row,column;

public double maxValue;

public Location(int row, int column, double maxValue){

this.row = row;

this.column =column;

this.maxValue = maxValue;

}

}

TestLocation.java

import java.util.Scanner;

public class TestLocation {

public static void main(String[] args) {

Scanner scan = new Scanner(System.in);

System.out.print("Enter the number of rows and columns in the array: ");

int rows = scan.nextInt();

int cols = scan.nextInt();

double d[][] = new double[rows][cols];

System.out.print("Enter the array:");

for(int i=0; i<d.length; i++){

for(int j=0; j<d[i].length; j++){

d[i][j] = scan.nextDouble();

}

}

Location l = locateLargest(d);

System.out.println("The location of the largest element is "+l.maxValue+" at ("+l.row+", "+l.column+")");

}

public static Location locateLargest(double[][] a){

double max = a[0][0];

int row =0 , col=0;

for(int i=0; i<a.length; i++){

for(int j=0; j<a[i].length; j++){

if(max<a[i][j]){

max = a[i][j];

row = i;

col = j;

}

}

}

Location l = new Location(row,col,max);

return l;

}

}

Output:

Enter the number of rows and columns in the array: 3
3
Enter the array:1
2
3
4
5
6
7
8
9
The location of the largest element is 9.0 at (2, 2)

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