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Please show and explain all work. Thank You. LOGICAL ADDRESS (14bits) STBR (bina

ID: 3700343 • Letter: P

Question

Please show and explain all work. Thank You.

LOGICAL ADDRESS (14bits) STBR (binary 16 bits) MAR (binary 16 bits) 1 001 000000 01 11 decimal decimal SEGMENT TABLE PAGE TABLE MAIN MEMORY 127 128 129 130 131 132 133 134 135 136 255 256 257 258 259 260 261 262 263 264 01000 01001 01010 01011 01100 01101 01110 01111 instruction 10000 10001 GIVEN THE FOLLOWING: process P5 needs to access the instruction in memory FILL IN ALL KNOWN VALUES ABOVE FOR THE FOLLOWING WORD IS 4 BYTES STBR MAR SEGMENT TABLE PAGE TABLE FRAME SIZE IS 512 BYTES TOTAL TOTAL NUMBER OF SEGEMENTS IN THE PROGRAM IS 8 LOGICAL ADDRESS IS GIVEN all answers in binary)

Explanation / Answer

ANSWER

GIVEN BY

Word is 4 bytes. Frame extent is 512 bytes = 29 bytes

So, offset field of elementary address strength of will be 9-2 = 7 bits

As the full amount digit of segment is given as 8 so, the piece integer playing field of the logical chat to will be 3 bits.

residual bits i.e 14 -(3 + 7 ) = 4 bits [as total size of consistent address is 14 bits] will be in the quantity of paper number grassland of the sound address.

commonsense address is specific as = 10010000000111

The original three bits are slice number

Therefore, piece number = 100

Next 4 bits are page figure

Then,

page number = 1000

at this occasion offset = 0000111

Now STBR is zilch but slice table base record .it contain the base address of the part stall (which is given as 127(in decimal)).

consequently STBR will surround the value 0000000001111111 .

now STBR + segment number = 127 + 4(as division number is 100) = 131

So in the division table 131th entry will hold the summon figure value i.e = 1000 = 8(in decimal)

Now top of page worktable address is 255.

So 255 + 8 = 263

So, 263th entry of the folio table will hold the cost of the edge figure where the lessons is there i.e = 01111

Now MAR will hold the speak to of this instruction which is not anything but edge number + offset = 0000011110000111.

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