Write a function swap that takes as arguments two pointers to integers. This fun

Question

Write a function swap that takes as arguments two pointers to integers. This function should swap the

values pointed to by the pointers passed to the function. So, if there were two pointers,

a

and

b

, which

point to integers 5 and 7, respectively, then after the function should run, then

a

should point to an integer

with value 7 and

b

should point to an integer with a value of 5.

Write a program that prompts a user to enter 15 integers. The program should store those integers in an

array. Then use the function you wrote to swap the 0th element with the 7th, the 8th with the 3rd, and the

14th with the 0th (in that order). The program should then print the values stored by the array after the

swaps. The output of the program should look like this:

Enter 15 integers:

0 1 2 3 4 5 6 7 8 9 10 11 12 13 14

Swapped array:

14 1 2 8 4 5 6 0 3 9 10 11 12 13 7

Explanation / Answer

#include <stdio.h>
void swap(int *a, int *b) {
int t = *a;
*a = *b;
*b=t;
}
int main()
{
int a[15],i;
printf("Enter 15 integers: ");
for(i=0;i<15;i++) {
scanf("%d", &a[i]);
}
swap(&a[0],&a[7]);
swap(&a[8],&a[3]);
swap(&a[14],&a[0]);
  
printf("Swapped array: ");
for(i=0;i<15;i++) {
printf("%d ", a[i]);
}
printf(" ");
  
return 0;
}

Output:

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