You are given the IP address block 17 2 . 1 6 . 2 2 4 . 0 with the subnet mask 2
ID: 3705476 • Letter: Y
Question
You are given the IP address block 172.16.224.0 with the subnet mask 255.255.240.0 and told to design a system that supports at least 14 subnets (You may end up supporting more subnets but each subnet must support as many hosts as possible while not violating this constraint). All subnets are expected to be of equal capacity in terms of number of hosts supported (in other words, no VLSM). Note that your last subnet may not be the 14th one.
(Enter all the IP address and subnet mask answers in dotted-decimal notation in the spaces provided.)
You are given the IP address block 192.168.112.0 / 20 and told to use this network to build subnets (as many as possible) that will support at least 120 hosts per subnet.All subnets are expected to be of equal capacity in terms of number of hosts supported (in other words, no VLSM).
(Enter all answers in dotted-decimal format in the space provided.)
You are given the IP address block 172.16.224.0 with the subnet mask 255.255.240.0 and told to design a system that supports at least 14 subnets (You may end up supporting more subnets but each subnet must support as many hosts as possible while not violating this constraint). All subnets are expected to be of equal capacity in terms of number of hosts supported (in other words, no VLSM). Note that your last subnet may not be the 14th one.
- How many assignable hosts can each subnet support? [A]
- What is the new subnet mask in dotted-decimal notation? [B]
- What is the first assignable host address on the first subnet? [C]
- What is the broadcast address for this first subnet? [D]
- What is the last assignable host address on the last subnet? [E]
(Enter all the IP address and subnet mask answers in dotted-decimal notation in the spaces provided.)
You are given the IP address block 192.168.112.0 / 20 and told to use this network to build subnets (as many as possible) that will support at least 120 hosts per subnet.All subnets are expected to be of equal capacity in terms of number of hosts supported (in other words, no VLSM).
- What is the subnet mask in dotted-decimal notation that you need to use to meet this requirement? [F]
- How many subnets will this produce? [G]
- What is the network address for the last subnet? [H]
(Enter all answers in dotted-decimal format in the space provided.)
Explanation / Answer
a) subnetting is the technique used to divide the large pool of IP Address to the smaller pools for use.
IP: 172.16.224.0 and subnet mask 255.255.240.0 is equivalent to 172.16.224.0/20
IP address is 32 bits long, with a subnet of 20 bit we have 12 bits for the host address.
Now we have to divide this big pool to at least 14 smaller pools.
to create the 14 smaller pools we need to use 4 bit from the host address for subnet. so we are left with 8 bit host adrress for smaller pools
ANS: 8 bit host address can support 2^8 (i.e 256) host address
b) new subnet will be 20 + 4 bit long i.e 255.255.255.0
c) the first subnet will be 172.16.224.0/8, so the first host will be 172.16.224.0
d) The broadcast address for an IPv4 host can be obtained by performing a bitwise OR operation between the bit complement of the subnet mask and the host's IP address. In other words, take the host's IP address, and set to '1' any bit positions which hold a '0' in the subnet mask. For broadcasting a packet to an entire IPv4 subnet using the private IP address space 172.16.224.0/8, which has the subnet mask 255.255.255.0, the broadcast address is 172.16.224.0 | 0.0.0.255 = 172.16.224.255.
e) Last subnet will be 172.16.238.0/8, so its last address will be 172.16.238.255.
f). for 120 host we need 7 bit ( 2^7 > 120). So new subnet will be 20 + 7 = 27 bit long
its decimal representation will be 255.255.255.224
g). 2^7 that is 128.
h). 192.168.127.224/5
P.S. Boldened Text is the answer for each part.
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