I need help modifying this python program without using with or any lists, this

Question

I need help modifying this python program without using with or any lists, this includes split.

import sys

for i in range(1, len(sys.argv)):

grade = 0

count = 0

for char in sys.argv[i]:

if char == ',':

if count == 0:

count += 1

print(': ', end='')

else:

print(' ', end='')

else:

print(char, end='')

print()

this program reformats sys.argv input: Mary,IT3233,B John,IT2430,A
Joe,IT3233,A Bob,IT2430,B.

i need it to ALSO:

Extend it such that if the grade is invalid, skip it. Valid grades: A, B, C, D, F.

Extend further such that you count the number of distinct courses and distinct grades for valid grades.
Output for above would be IT 3233 – 2, IT 2430 – 2, A-2, B-2.

Explanation / Answer

Please find the below program with necessary changes :

import sys

#list is declared to store all the command-line argument value and compare them

myList = []

#character type variable is deaclared to store each character from command-line

a = ''

for i in range(1, len(sys.argv)):

grade = 0

count = 0

for char in sys.argv[i]:

if char == ',':

#adding each word to list

myList.append(a)

print(a)

a = ''

if count == 0:

count += 1

print(': ', 'end=' , count)

else:

print(' ', 'end=' , count)

else:

#adding each character to make a complete word seperated by ','

a=a+char

print(a)

#appending the grade to the myList

myList.append(a)

#removing the names from myList

y = len(myList)

myList.pop(y - 3)

print(myList)

#removing the entry with invalid grade

if a!='A' and a!='B' and a!='C' and a!='D' and a!='F':

x = len(myList)

print(x)

myList.pop(x - 1)

myList.pop(x - 2)

myList.pop(x - 3)

print(myList)

#counting number of distinct courses and distinct grades for valid grades

for i in range(len(myList)):

count = 1

for j in range(i+1, len(myList)):

if myList[i] == myList[j]:

count += 1

if count > 1:

print myList[i],count

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