S artaySwap Main Page Problems- Solve a Problem O BJP4 Self-Check 7.19: Referenc

Question

S artaySwap Main Page Problems- Solve a Problem O BJP4 Self-Check 7.19: ReferenceMystery1 avrite Language/Type: &Java; arrays reference semantics Author: Marty Stepp (on 2016/09/08) The following program produces 4 lines of output Write each line of output below as it would appear on the console import java.util. for Arrays class public class ReferenceMysteryl( public static void main(Stringl] args) t int x 0; int [ ] a new int[4]; nystery(x, a); System.out.printin(xArrays.tostring(a)); nystery(x, a); System.out.println(xArrays.tostring(a)); public static void mystery(int x, int[) )( x+4 alx) System out.printnxArrays.tostring(a)); line 1 2 (o,0,s,e line 2 1 to.e,1,ej line 3 te,e.1.1 ine 4 2 te,e,i. Submit B e

Explanation / Answer

Change the value of variable doesn't reflect in the calling function.

But, Change of array value will reflect in the calling function.

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value of x before the call to mystery(x,a); is 1

So, First call to the function is

mystery([0,0,0,0], 1)

So, x is incremented by 1. So x becomes 2 and x[2] becomes 1

So It prints 2 [0, 0, 1, 0]

In the main function it prints

1 [0, 0, 1, 0]

Because change of variable doesn't reflects and array will reflects in main function

In main, x value is incremented by 1 more. So, x value is 2

Second call becomes mystery([0,0,1,0], 2)

In mystery, x is incremented by 1 so, It becomes 3 and changes the array value x[3] = 1

So, It prints 3 [0, 0, 1, 1]

In the main function it prints

2 [0, 0, 1, 1]

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