For the Class A network 5.0.0.0 which has been subnetted into 2 subnets, fill in

Question

For the Class A network 5.0.0.0 which has been subnetted into 2 subnets, fill in the following chart (dotted decimal).

     
   Network Address   Broadcast Address   Host Address Range
First Subnet          
Second Subnet          

For the Class A network 5.0.0.0 which has been subnetted into 4 subnets, fill in the following chart (dotted decimal).

   Network Address   Broadcast Address   Host Address Range
First Subnet          
Second Subnet          
Third Subnet          
Fourth Subnet          

Write the network address and broadcast address for the following IP Address/Subnet Mask combinations. Show your work using binary analysis but express your final answer in dotted decimal.

IP = 10.10.125.67       SM = 255.255.128.0

Network Address =                               Broadcast Address =

IP = 10.10.253.46       SM = 255.255.128.0

Network Address =                               Broadcast Address =

IP = 10.172.172.172    SM = 255.240.0.0

Network Address =                               Broadcast Address =

Explanation / Answer

1. For the Class A network 5.0.0.0 which has been subnetted into 2 subnets, fill in the following chart (dotted decimal).

   Network Address   Broadcast Address   Host Address Range
First Subnet - 5.0.0.0/9 - 5.127.255.255 - (5.0.0.1 to 5.127.255.254)

Second Subnet - 5.128.0.0/9 - 5.255.255.255 - (5.128.0.1 to 5.255.255.254)

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2. For the Class A network 5.0.0.0 which has been subnetted into 4 subnets, fill in the following chart (dotted decimal).

   Network Address   Broadcast Address   Host Address Range
First Subnet - 5.0.0.0/10 - 5.63.255.255 - (5.0.0.1 to 5.63.255.254)

Second Subnet - 5.64.0.0/10 - 5.127.255.255 - (5.64.0.1 to 5.127.255.254)

Third Subnet - 5.128.0.0/10 - 5.191.255.255 - (5.128.0.1 to 5.191.255.254)

Fourth Subnet - 5.192.0.0/10 - 5.255.255.255 - (5.192.0.1 to 5.255.255.254)

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3. Write the network address and broadcast address for the following IP Address/Subnet Mask combinations. Show your work using binary analysis but express your final answer in dotted decimal.

A. IP = 10.10.125.67       SM = 255.255.128.0

Network Address = 10.10.0.0/17

Broadcast Address = 10.10.127.255

B. IP = 10.10.253.46 SM = 255.255.128.0

Network Address = 10.10.128.0/17

Broadcast Address = 10.10.255.255

C. IP = 10.172.172.172 SM = 255.240.0.0

Network Address = 10.160.0.0/12

Broadcast Address = 10.175.255.255

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