In JAVA WITHOUT ARRAYS , create a lottery game application. Generate three rando

Question

In JAVA WITHOUT ARRAYS, create a lottery game application. Generate three random numbers, each between 0 and 9. Allow the user to guess three numbers. Compare each of the user's guess to the three random numbers and display a message that includes the user's guess, the randomly determined three-digit number, and the amount of money the user has won as follows:

make certain that your application accommodates repeating digits. For example, if a user guesses 1,2, and 3, and the randomly generated digits are 1,1, and 1, do not give the user credit for three correct guesses - just one. Save the file as Lottery.java.

matching numbers award ($) any one matching 10 two matching 100 three matching not in order 1,000 three matching in exact order 1,000,000 no matches 0

Explanation / Answer

import java.util.Random;

import java.util.Scanner;

public class Driver {

public static void main(String[] args){

Random r = new Random();

int a = r.nextInt(10);

int b = r.nextInt(10);

int c = r.nextInt(10);

System.out.println("Enter the three numbers: ");

Scanner in = new Scanner(System.in);

int first = in.nextInt();

int second = in.nextInt();

int third = in.nextInt();

System.out.println(a);

System.out.println(b);

System.out.println(c);

if((first == a && second != b && third != c) && (first != a && second == b && third != c) && (first != a && second != b && third == c))

System.out.println("Award is 10");

else if((first == a && second == b && third != c) && (first == a && second != b && third == c) && (first != a && second == b && third == c))

System.out.println("Award is 100");

else if(first == a && second == b && third == c)

System.out.println("Award is 1,000,000");

else if (first != a && second != b && third != c)

System.out.println("Award is 0");

else

System.out.println("Award is 1,000");

}

}

**Comment for any further queries.

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