The C code below is for Exam 2 Program 1 . It now runs perfectly. Help me with E

Question

The C code below is for Exam 2 Program 1. It now runs perfectly. Help me with Exam 3 Program 2 and Exam 4 Program 1 from the picture above

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

void main()
{
   int i;
   char name[15];
   char grade;
   int homework1, homework2, homework3, exam1, exam1total, exam2, exam2total, totalhomework, totalexam, a, b, c, d, f;
   float percentage;
   exam1total = 0;
   exam2total = 0;
   a = b = c = d = f = 0;
   for(i = 0; i < 5; i++)
   {
      
       printf("enter a name ");
       gets_s(name, 15); //no placeholder
       printf("enter homework grades and exam scores ");
       scanf_s("%d%d%d%d%d", &homework1, &homework2, &homework3, &exam1, &exam2);
      
       exam1total += exam1; //examtotal = exam1total + exam1;
       exam2total += exam2;
       totalexam = exam1 + exam2;
       totalhomework = homework1 + homework2 + homework3;
       percentage = totalhomework / (float) 1.875 + totalexam / (float) 3.333;
      
       if (percentage < 0 || percentage > 100)
          {
            printf("invalid");
          }
      
      
       else if (percentage >= 90)
       {
           grade = 'A';
           a++;
          }
      
       else if (percentage >= 80)
       {
           grade = 'B';
           b++;
          }
      
       else if (percentage >= 70)
       {
           grade = 'C';
           c++;
          }
      
      
       else if (percentage >= 60)
       {
           grade = 'D';
           d++;
       }
      
        else
       {
           grade = 'F';
           f++;
       }
          
       printf(" %s Total Homework Points : %d Total Exam Points : %d Class Percentage: %0.2f Grade : %c ", //string - collection of chars.
             name, totalhomework, totalexam, percentage, grade); // \\ %d = int/unsigned int \\ %c char
       getchar(); //?????
      
      
   }
   printf(" average exam 1 score : %0.2f", exam1total / (float)5); //5 average scores a,b,c,d,f? or 5 other "things" **********
   printf(" average exam 2 score : %0.2f", exam2total / (float)5);
    printf(" Number of A's : %d Number of B's : %d Number of C's : %d Number of D's : %d Number of F's : %d ", a, b, c, d, f);
   system("PAUSE");

      
}

Exam 3 Program 2: Rewrite Exam 2 Program 1 using appropriate functions and parameter passing. You can include either void or non-void functions. Also, please include a structure chart for your program which you can either create by hand or on the computer. Your main should consist of only declarations and function calls. Exam 4 Program 1: Rewrite Exam 3 Program 2 using a looping statement. You may use either a while loop, do loop, or for loop. Please include a brief statement in a comment statement in your program stating the assumptions you made to pick your looping statement. That is, if the loop is deterministic or indeterministic and if the loop is entrance-controlled or exit-controlled

Explanation / Answer

The below C code uses two functions getMarks() and showResult().It takes as input the parameters that are required to be manipulted ahead like name,exam1total,exam2total,totalexam,totalhomework and percentage.The getMarks function is used to read the marks from the user and then calcultes the total for the exams and homeworks.It then passes these values again to the showResult function and it calculates the percentage and displays the result accordingly.

I am using pointers to pass data from main to these functions as the changes made into the values of these variables has to be persistent.

CODE:

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
void getMarks(char *name,int *e1total,int *e2total,int *totalexam,int *totalhomework,float *percentage)
{
int homework1, homework2, homework3, exam1, exam2;

printf("Enter a name ");
gets(name);
printf("Enter homework grades and exam scores ");
scanf("%d%d%d%d%d", &homework1, &homework2, &homework3, &exam1, &exam2);

*e1total += exam1;
*e2total += exam2;
*totalexam = exam1 + exam2;
*totalhomework = homework1 + homework2 + homework3;

}
void showResult(char *name,int *e1total,int *e2total,int *totalexam,int *totalhomework,float *percentage)
{
char grade;
*percentage = *totalhomework / (float) 1.875 + *totalexam / (float) 3.333;
int a , b, c, d, f ;
a = b = c = d = f = 0;
if (*percentage < 0 || *percentage > 100)
{
     printf("invalid");
}

else if (*percentage >= 90)
{
     grade = 'A';
     a++;
}

else if (*percentage >= 80)
{
     grade = 'B';
     b++;
}

else if (*percentage >= 70)
{
     grade = 'C';
     c++;
}

else if (*percentage >= 60)
{
    grade = 'D';
    d++;
}

else
{
     grade = 'F';
     f++;
}

printf(" %s Total Homework Points : %d Total Exam Points : %d Class Percentage: Grade : %c ",name, *totalhomework, *totalexam, *percentage, grade);
getchar();
printf(" average exam 1 score : %0.2f", *e1total / (float)5); //5 average scores a,b,c,d,f? or 5 other "things" **********
printf(" average exam 2 score : %0.2f", *e2total / (float)5);
printf(" Number of A's : %d Number of B's : %d Number of C's : %d Number of D's : %d Number of F's : %d ", a, b, c, d, f);
system("PAUSE");

}

void main()
{
    int i;
    char name[15];
    char grade;
    int homework1, homework2, homework3, exam1,
   exam1total=0, exam2, exam2total=0, totalhomework=0, totalexam=0,
   a, b, c, d, f;
    float percentage=0;
    exam1total = 0;
    exam2total = 0;
    a = b = c = d = f = 0;
    getMarks(name,&exam1total, &exam2total,&totalexam,&totalhomework,&percentage);
    showResult(name,&exam1total, &exam2total,&totalexam,&totalhomework,&percentage);

}

OUTPUT:

For the exam4 program1,that uses loops to function itself has already been written by you.It doesn't need any modifications as far as the requirements are concerned.It assumes that the user will input the marks for a fixed number of students and hence it runs 5 times.So,the above code is already fine.The for loop is an entry control loop as it checks the condition that is to be tested before entering the statements to be executing inside it.

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