Hello, im not sure how to do this as i tried comparing the two vectors but the d

Question

Hello, im not sure how to do this as i tried comparing the two vectors but the dimensions are not the same, not sure how to go about it.

Define a third row vector, Button, that is the same length as the frequency and duration vectors. Then write code to compare each element of the frequency vector to the 4 x 2 matrix to identify which button number to assign to each element of the Button vector. For example, the Button vector for the 8 notes shown in Figure 7 would be Button = [2,2,3,1,2,3,2,2].

Note Frequency Duration Button Frequency 440 392 330 262 392 392 330 440 392 330 392 392 0.5 0.5 0.5 0.5 1 1 0.5 0.5 1 4

Explanation / Answer

#include <vector>

#include <map>

using namespace std;

int main()

{

// 4x2 Matrix conating the Frequency and corresponding Button

// The first part of the pair is the frequency and the second the the button

map<int, int> buttons =

{

make_pair(440, 1),

make_pair(392, 2),

make_pair(330, 3),

make_pair(262, 4)

};

vector<char> Notes = { 'G', 'G', 'E', 'A', 'G', 'E', 'G', 'G' };

vector<int> Frequencies = { 392, 392, 330, 440, 392, 330, 392, 392 };

vector<double> Duration = { 0.5, 0.5, 0.5, 0.5, 1, 1, 0.5, 0.5 };

// Vector used to store the Button values

vector<int> Button;

// For each frequency from the vector of frquencies, find corresponding button

// value and store it in the Button vector

for (int f : Frequencies)

{

Button.emplace_back(buttons[f]);

}

}

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