* This function computes the area of a series of squares and circles. Specifical
ID: 3716149 • Letter: #
Question
* This function computes the area of a series of squares and circles. Specifically, we consider a series * of squares and circles in which each successive shape is inscribed in the other. This function sums * the area of each shape and returns it. At each level of recursion, the funciton switches between oa circle being inscribed by a square, and a square being inscribed by a circle. * A circle inscribed in a square has the diameter equal to the width of a square. A square inscribed in a *circle has a diagonal length equal to the diameter of the circle. *Given a square of width x, the circle inscribed will have a radius of size x/2. Thus, it will have an area * of pi * (x/2)A2 * Given a circle of radius x, the inscribed square will have a diagonal length of size 2x. Thus, it will have a width of 2x / sartC2) -sat2)x. It will thus have an area of 2*xA2) *The function recursively computes these areas until depth1. Then the area of the last shape is *returned * @param square If the shape to compute the area for is a square or a circle. * @param length If a square, the width/height of the square. If a circle, the radius of the circle. * @param depth The recursion depth. When depth 1 the area of the final shape is computed and returned; *recursion is stopped (the base case) * ereturn The sum value of sequentially inscribed squares and circles. public static double circledSquared(boolean square, double Length, int depth)Explanation / Answer
Hi. please find the answer above.. i have given comments so that it is very easy for you to understand the flow. In case of any doubts, please ask in comments. If the answer helps you, please upvote. Thanks!
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.