In the above code, two strings are evaluated using the equivalency operator. Why

Question

In the above code, two strings are evaluated using the equivalency operator. Why can this be a problem, and what other methods are offered by Java for working with characters and strings?

import java.util.Scanner; public class TryToCompareStrings public static void main(String[] args) String aName"Carmen"; String anotherName; Scanner input new Scanner(System.in) System.out.print("Enter your name>") anotherNmeinput.nextLineO: if(aNameanothen Name) System.out.println(aNameequals " + anotherName); else System.out.println (aName " does not equal "anotherName);

Explanation / Answer

Hi,

equivalency operator compares references not values. Where as equals() compares original values of the string.

String class provides 2 methods

1) equals(Object second) - compare string to the specified object.

2) equalsIgnoreCase(String second) - compares String to second string, by ignoring case

I have written the below java program by using equals.

import java.util.Scanner;

public class CmTest {

public static void main(String[] args) {

String aName = "Carmen";

String anotherName;

Scanner input = new Scanner(System.in);

System.out.println("Enter your name >");

anotherName = input.nextLine();

if (aName.equals(anotherName)) {

System.out.println(aName + " Equals " + anotherName);

} else {

System.out.println(aName + " Not Equals " + anotherName);

}

}

}

Output:

Enter your name >
Carmen
Carmen Equals Carmen

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.