public class BadNews { public static final int MAX_ODD = 21; public static void

Question

public class BadNews {
public static final int MAX_ODD = 21;

public static void writeOdds() {
// print each odd number
for (int count = 1; count <= (MAX_ODD - 2); count++) {
System.out.print(count + " ");
count = count + 2;
}

// print the last odd number
System.out.print(count + 2);
}

public static void main(String[] args) {
// write all odds up to 21
writeOdds();

// now, write all odds up to 11
MAX_ODD = 11;
writeOdds();
}
}

GIve Me a Hint! Show Header O BJP4 Self-Check 2.34: BadNewS Favorite Language/Type: é Java errors for loops Author: Marty Stepp (on 2016/09/08) . Hint: The program tries to use a method to reduce redundancy, but this may not be the best place for it, based on what we have already learned. Try rewriting the code without the method Suppose that you are trying to write a program that produces the following output using loops. The program below is an attempt at a solution, but it contains at least four major errors. Identify and fix them all 1 3 5 7 911 13 15 17 19 21 1 3 5 7 9 11 3 Revert lype your solution here 1 public class BadNews { 2 public static final int MAX_ODD -21; 4 public static void writeOdds() [ // print each odd number for (int count 1; count

Explanation / Answer

Errors are corrected and comments provided with in the program

public class BadNews{
// Error 1 Below assignment can not be final since further down the program 11 reassigned
public static int MAX_ODD = 21;

public static void writeOdds() {
// Error 2 Compile time error count has to be defined out side for loop
// print each odd numbe
int count = 1;
// Error 3 Logic error since count is incremented by 2 with in loop there is not need to increment again
for (count = 1; count <= (MAX_ODD - 2);) {
System.out.print(count + " ");
count = count + 2;
}
// Error 4 add new line character to send next output to next line
// print the last odd number
System.out.print((count + 2 )+" ");
}

public static void main(String[] args) {
// write all odds up to 21
writeOdds();
// now, write all odds up to 11
MAX_ODD = 11;
writeOdds();
}
}

Output

1 3 5 7 9 11 13 15 17 19 21

1 3 5 7 9 11

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