Assembly Language var01 is an SBYTE with magnitude 1 less that the maximum possi

Question

Assembly Language
var01 is an SBYTE with magnitude 1 less that the maximum possible positive SBYTE value. var02 is an SBYTE with a magniture 1 more than the minimum (most negative) SBYTE value. (This means +1 added to minimum SBYTE value). var03 is a WORD that is 5 less than the maximum possible WORD value. var04 is an SWORD with magnitude 5 more than the minimum possible (most negative) SWORD value. (This is +5 added to the minimum SWORD value). var05 is an SDWORD with magnitude 10016 more than the minimum (most negative) SDWORD value. (This means +10016 added to the minimum SDWORD value) var06 is an SDWORD with magnitude equal to the most negative SDWORD value. All magnitudes should be expressed as (possibly signed) base 10 numbers. The slides have a table that should be helpful. In the .code portion of the program do the following: zero out eax and ebx move var01 to al move var02 to ah add ah to al and put result in al move 10000000b to ah subtract ah from al and put result in al move var03 to ax move var04 to bx add ax to bx and put result in bx move var05 to eax subtract var06 from eax Assembly Language
var01 is an SBYTE with magnitude 1 less that the maximum possible positive SBYTE value. var02 is an SBYTE with a magniture 1 more than the minimum (most negative) SBYTE value. (This means +1 added to minimum SBYTE value). var03 is a WORD that is 5 less than the maximum possible WORD value. var04 is an SWORD with magnitude 5 more than the minimum possible (most negative) SWORD value. (This is +5 added to the minimum SWORD value). var05 is an SDWORD with magnitude 10016 more than the minimum (most negative) SDWORD value. (This means +10016 added to the minimum SDWORD value) var06 is an SDWORD with magnitude equal to the most negative SDWORD value. All magnitudes should be expressed as (possibly signed) base 10 numbers. The slides have a table that should be helpful. In the .code portion of the program do the following: zero out eax and ebx move var01 to al move var02 to ah add ah to al and put result in al move 10000000b to ah subtract ah from al and put result in al move var03 to ax move var04 to bx add ax to bx and put result in bx move var05 to eax subtract var06 from eax Assembly Language
var01 is an SBYTE with magnitude 1 less that the maximum possible positive SBYTE value. var02 is an SBYTE with a magniture 1 more than the minimum (most negative) SBYTE value. (This means +1 added to minimum SBYTE value). var03 is a WORD that is 5 less than the maximum possible WORD value. var04 is an SWORD with magnitude 5 more than the minimum possible (most negative) SWORD value. (This is +5 added to the minimum SWORD value). var05 is an SDWORD with magnitude 10016 more than the minimum (most negative) SDWORD value. (This means +10016 added to the minimum SDWORD value) var06 is an SDWORD with magnitude equal to the most negative SDWORD value. All magnitudes should be expressed as (possibly signed) base 10 numbers. The slides have a table that should be helpful. In the .code portion of the program do the following: zero out eax and ebx move var01 to al move var02 to ah add ah to al and put result in al move 10000000b to ah subtract ah from al and put result in al move var03 to ax move var04 to bx add ax to bx and put result in bx move var05 to eax subtract var06 from eax

Explanation / Answer

.386

.model flat, stdcall

.stack 4096

.data

var01 SBYTE 126    ;max value of sbyte is 127 so 1 less than that is 126

var02 SBYTE -127    ;minimum value of sbyte is -128 so 1 more than that is -127

var03 WORD 65531    ;maximum value of word is 65536 so 5 less than that is 65531

var04 SWORD -32763    ;minimum value of sword is -32768 so 5 more than that is -32763

var05 SDWORD 2147473632    ;minimum value of sdword is 2,147,483,648 so 10016 more than that is 2147473632

var06 SDWORD 2,147,483,648    ;minimum value of sdword is 2,147,483,648

.code

mov eax, 0    ;setting eax to zero

mov ebx, 0    ;setting ebx to zero

mov al,var01    ;moving value in var01 to al

mov ah,var02    ;moving value in var02 to ah

add al,ah    ;adding ah to al and putting result to al

mov ah,10000000b    ;moving 10000000 binary number to ah

sub [al],ah    ;subtracting ah from al and storing the result in al

mov ax,var03    ;moving value in var03 to ax

mov bx,var04    ;moving value in var04 to bx

add bx,ax    ;adding ax to bx and storing the result in bx

mov eax,var05    ;moving value in var05 to eax

sub [eax],var06    ;subtracting the value in var06 from eax

END

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