Write a C language program that reads input until it encounters a ‘#’ character.

Question

Write a C language program that reads input until it encounters a ‘#’ character. Count all the occurrences of the letter sequence “is” in that order.

A screenshot showing the series of values tested.

Test a minimum of 7 cases including:

“is this working#” (result -> 2) “wishing is what wishers do#” (result -> 3) “Mississippi#” (result -> 2) “Missouri#” (result -> 1) “isiissiiisss#” (result-> 3) “ssss si s i#” (result -> 0) “i s iiiiii#” (result -> 0) A listing of your C program Be sure your name and CWID is printed by the program. Test with a minimum of the cases I have presented, more is better.

Notes: This problem does not break easily into functions, for this assignment, writing all the logic in “main” is acceptable.

Explanation / Answer

#include <stdio.h>
#include <string.h>

char str[100], sub="is";
int count = 0, count1 = 0;

void main()
{
int i, j, l, l1, l2;
//Get the input string from user
printf(" Enter a string : ");
scanf("%[^ ]s", str);

l1 = strlen(str);

  
l2 = strlen(sub);

//check for thr occurance of 'is' in the string
for (i = 0; i < l1;)
{
j = 0;
count = 0;
while ((str[i] == sub[j]))
{
count++;
i++;
j++;
}
if (count == l2)
{
count1++;
count = 0;
}
else
i++;
}   
printf("%s occurs %d times in %s", sub, count1, str);
}

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