Evaluate the truth values of the following conditions given the values of the de

Question

Evaluate the truth values of the following conditions given the values of the declared variables. NOTE: Conditions formed using relational or equality operators (>, <, >=, <=, ==, !=) are relational conditions. Conditions formed using logical operators [&& (AND), || (OR), & (boolean AND), | (boolean inclusive OR), ^ (boolean exclusive OR) are complex conditions.

Variables

boolean goodEssay = false;

double gpa = 3.0;

boolean technicalDegree = true;

Conditions:Evaluate then indicate the truth value produced by the relational conditions and the joins. NOTE: Change in variable values do not carry over to next evaluation.

Truth Value of Complex Conditions

F (short-circuit)

goodEssay && technicalDegree || gpa > 3.0

FF

goodEssay && technicalDegree || gpa > 3.0

False

False

goodEssay && (technicalDegree == false) && (gpa >= 3.5)

!(technicalDegree && goodEssay)

goodEssay = true;

goodEssay & !(technicalDegree & (gpa != 3.0))

goodEssay ^ technicalDegree || (gpa == 5.0)

gpa = 3.5;

(goodEssay || technicalDegree) && (gpa > 3.25))

goodEssay & technicalDegree | (gpa == 4.0)

!goodEssay | (technicalDegree ^ (gpa >= 3.0))

Variables

int peopleInvited = 10;

double catering = 5000.00;

double facilityFee = 500.00;

Conditions:Evaluate then Indicate the truth value produced by the relational conditions and the joins. NOTE: Change in variable values do not carry over to next evaluation.

Truth Value of Complex Conditions

(facilityFee > 350.00) && (catering > 3000.00) | (++peopleInvited >= 10)

(peopleInvited > 10) || (catering >= 5000.00) && !(facilityFee < 500.00)

facilityFee = 1000.00

(peopleInvited >= 10) & (catering != 5000.00) || !(facilityFee < 1000.00)

Variables

boolean goodEssay = false;

double gpa = 3.0;

boolean technicalDegree = true;

Explanation / Answer

goodEssay && (technicalDegree == false) && (gpa >= 3.5)

explanation: goodEssay = false(0),technicalDegree = true(1), gpa = 3.0

0 && (1==0) && (3.0 >= 3.5) therefore, [1 == 0 is false(0)]

=> 0 && (0) && (3.0 >= 3.5) therefore, [3.0 >= 3.5 is false(0)]

   => 0 && (0) && (0)

=>0 (false)

False

!(technicalDegree && goodEssay)

Explanation :

!(1 && 0) therefore [1 && 0 is 0(false)]

=> !(0) therefore [!0(negation of 0) is 1(true)]

=> 1

True

goodEssay = true;

goodEssay & !(technicalDegree & (gpa != 3.0))

Explanation :

=> 1& !(1& (3.0 != 3.0))

=> 1& !(1& (false))

=> 1& !(1& (0))

=> 1& !(0)

=> 1& 1

=> 1

True

goodEssay ^ technicalDegree || (gpa == 5.0)

Explanation :

=> 0 ^ 1|| (3.0== 5.0)

=> 0 ^ 1|| (false)

=> 0 ^ 1|| (0)

=>1 || (0)

=>1

True

gpa = 3.5;

(goodEssay || technicalDegree) && (gpa > 3.25))

Explanation :

=>(0|| 1) && (3.5 > 3.25))

=>(0|| 1) && (true))

=>(0|| 1) && (1))

=>(0|| 1) && 1)

=>(1) && 1) [error : braces mismatch] if it is typo

=>1

True

goodEssay & technicalDegree | (gpa == 4.0)

Explantion :

=> 0& 1| (3.0== 4.0)

=> 0& 1| (false)

=> 0& 1| (0)

=>0| (0)

=>0

False

!goodEssay | (technicalDegree ^ (gpa >= 3.0))

Explanation :

=> !0 | (1 ^ (3.0 >= 3.0))

=> !0 | (1 ^ (true))

=> !0 | (1 ^ (1))

=> !0 | (1 ^ 1)

=> !0 | (0)

=> 1 | (0)

=> 1

True

Variables:

int peopleInvited = 10;

double catering = 5000.00;

double facilityFee = 500.00;

(facilityFee > 350.00) && (catering > 3000.00) | (++peopleInvited >= 10)

Explanation :

=> (500.00 > 350.00) && (5000.00 > 3000.00) | (++10 >= 10)

=> (500.00 > 350.00) && (5000.00 > 3000.00) | (11 >= 10)

=> (true) && (true) | (true)

=> (1) && (1) | (1)

=> 1

True

(peopleInvited > 10) || (catering >= 5000.00) && !(facilityFee < 500.00)

Explanation :

=> (10 > 10) || (5000.00 >= 5000.00) && !(500.00 < 500.00)

=> (false) || (true) && !(false)

=> (0) || (1) && !(0)

=> (0) || (1) && 1

=> 0 || 1 && 1

=> 1

True

facilityFee = 1000.00

(peopleInvited >= 10) & (catering != 5000.00) || !(facilityFee < 1000.00)

Explanation :

=> (10 >= 10) & (5000.00 != 5000.00) || !(1000.00 < 1000.00)

=> (true) & (false) || !(false)

=> (1) & (0) || !(0)

=> 1 & 0 || 1

=> 0 || 1

=> 1

True

goodEssay && (technicalDegree == false) && (gpa >= 3.5)

explanation: goodEssay = false(0),technicalDegree = true(1), gpa = 3.0

0 && (1==0) && (3.0 >= 3.5) therefore, [1 == 0 is false(0)]

=> 0 && (0) && (3.0 >= 3.5) therefore, [3.0 >= 3.5 is false(0)]

   => 0 && (0) && (0)

=>0 (false)

False

!(technicalDegree && goodEssay)

Explanation :

!(1 && 0) therefore [1 && 0 is 0(false)]

=> !(0) therefore [!0(negation of 0) is 1(true)]

=> 1

True

goodEssay = true;

goodEssay & !(technicalDegree & (gpa != 3.0))

Explanation :

=> 1& !(1& (3.0 != 3.0))

=> 1& !(1& (false))

=> 1& !(1& (0))

=> 1& !(0)

=> 1& 1

=> 1

True

goodEssay ^ technicalDegree || (gpa == 5.0)

Explanation :

=> 0 ^ 1|| (3.0== 5.0)

=> 0 ^ 1|| (false)

=> 0 ^ 1|| (0)

=>1 || (0)

=>1

True

gpa = 3.5;

(goodEssay || technicalDegree) && (gpa > 3.25))

Explanation :

=>(0|| 1) && (3.5 > 3.25))

=>(0|| 1) && (true))

=>(0|| 1) && (1))

=>(0|| 1) && 1)

=>(1) && 1) [error : braces mismatch] if it is typo

=>1

True

goodEssay & technicalDegree | (gpa == 4.0)

Explantion :

=> 0& 1| (3.0== 4.0)

=> 0& 1| (false)

=> 0& 1| (0)

=>0| (0)

=>0

False

!goodEssay | (technicalDegree ^ (gpa >= 3.0))

Explanation :

=> !0 | (1 ^ (3.0 >= 3.0))

=> !0 | (1 ^ (true))

=> !0 | (1 ^ (1))

=> !0 | (1 ^ 1)

=> !0 | (0)

=> 1 | (0)

=> 1

True

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