e) // calling method doublelI data new double[3]: int size 3 methodi(data, size,

Question

e) // calling method doublelI data new double[3]: int size 3 methodi(data, size, 3.1) Ill show what is in the array data at this point // show what is in the integer size at this point: public static void methodídoublel source, int size, double value) t size size-1, source[sizel value; Heap Main Stack Frame Identifier Address Contents 1000 1001 1002 1003 1004 1005 1006 1007 1008 1009 1010 1011 1012 Identifier Address Contents 101 102 103 Method Stack Frame Identifier Address Contents 200 201 202

Explanation / Answer

Solution:

Main method stack

identifier size, content 3

identifier i content 0, 1, 2

Method stack frame:

identifier size, content 2

identifier source[2], content 3.1

Heap:

The array is generated at run time

so heap will contain the array elements

data[0] = 0.0

data[1] = 0.5

data[2] = 1.0

since double contains 4 bytes of address from 1000 to 1011 the content of the array data will be stored in the address.

I hope this helps if you find any problem. Please comment below. Don't forget to give a thumbs up if you liked it. :)

Related Questions

Navigate

• Browse (All)
• Browse E
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.