7. Take the first smaller subnet from problem #6, and subnet it further so that

Question

7. Take the first smaller subnet from problem #6, and subnet it further so that you have four subnets of 8 IP addresses each. Find the following: the new subnet mask, how many new subnets you have, and what the network address is for each.

subnets from problem #6

subnet 1:
----------
network address: 192.168.0.0
available ip addresses: 30
broadcast address: 192.168.0.31

subnet 2:
----------
network address: 192.168.0.32
available ip addresses: 30
broadcast address: 192.168.0.63

subnet 3:
----------
network address: 192.168.0.64
available ip addresses: 30
broadcast address: 192.168.0.95

subnet 4:
----------
network address: 192.168.0.96
available ip addresses: 30
broadcast address: 192.168.0.127

subnet 5:
----------
network address: 192.168.0.128
available ip addresses: 30
broadcast address: 192.168.0.159

subnet 6:
----------
network address: 192.168.0.160
available ip addresses: 30
broadcast address: 192.168.0.191

subnet 7:
----------
network address: 192.168.0.192
available ip addresses: 30
broadcast address: 192.168.0.223

subnet 8:
----------
network address: 192.168.0.224
available ip addresses: 30
broadcast address: 192.168.0.255

Explanation / Answer

network address: 192.168.0.0
available ip addresses: 30
broadcast address: 192.168.0.31

It can be divided into 4 subnets of 8 IP addresses each
subnet 1:
-----------
network address: 192.168.0.0

subnet 2:
-----------
network address: 192.168.0.8

subnet 3:
-----------
network address: 192.168.0.16

subnet 4:
-----------
network address: 192.168.0.24

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