D Question 2 6 pts The timing diagram below illustrates a system in which operat

Question

D Question 2 6 pts The timing diagram below illustrates a system in which operations occur as three consecutive clock cycles. Actions taking place in clock cycle 1 are scalable: that is, if the clock cycle time changes, the actions can be sped up or slowed down correspondingly. In cycle 2, the action process 1 requires 25 ns and in clock cycle 3 the action process 2 requires 32 ns. If the clock cycle is less than the time required for process 1 or process 2, then one or more wait cycles have to be inserted for the process to complete. What is the time to complete the operation if the clock cycle time is 35 ns? Cycle Cycle 2 Cycle 3 Clock 25 ns 32 ns Cycle and process times O 105 ns 140 ns 175 210 0 earch

Explanation / Answer

Answer : A) 105 ns

Explanation :

here clock cylce 1 can be of any size , hence clock cycle time 35ns is enough for first cycle.

In second cycle, the process 1 needs at least 25ns . As clock cycle time is 35 ns, there is no need to add wait clock cycle. Hence cycle 2 can be finished in 35ns.  

In third cycle, process 2 time is 32ns and clock cycle time is 35ns. Hence process 2 can be finished in one cycle.

Hence total time needed = 35 + 35 + 35 = 105 ns.

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