Assume that the compiler performs no optimization and that all code runs on the

Question

Assume that the compiler performs no optimization and that all code runs on the processor exactly as written. Also assume that no library calls will fail. #include 0001: 0002: #include 0003: #de fine NUM THREADS 4 0004: char array [NUM THREADS+21: 0005: int pos =0; 0006: char outs [9] # 0011 : 0012: 0013: 0014 char outs[index]: 0015 : 0016: return NULL 0017: 0018: int main() 0019: void * work (void* id) int index (* ( (int*) id)) *2; = array [pos++] = c; 0020: char three'z 0021: int i; 0022: pthread t tid [NUM THREADS] 0023 : for (i 0; í

Explanation / Answer

Program:

#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <pthread.h>
#define NUM_THREADS 4
char array[NUM_THREADS+2];
int pos = 0;
char outs[9] = { 'a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i' };
void * work(void* id)
{
int index = (*((int*)id)*2);
char c = outs[index];
array[pos++] = c;
return NULL;
}
int main()
{
char three = 'z';
int i;
pthread_t tid[NUM_THREADS];
for(i =0;i<NUM_THREADS;i++)
pthread_create(&(tid[i]), NULL, work, (void*)(&i));
for(i=0;i<NUM_THREADS;i++)
pthread_join(tid[i], NULL);
array[pos++] = three;
array[pos]='';
printf(" %d ",strlen(array));
exit(0);
}

Output: The above program doesnot print any value

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