what you are about to read is a copy paste of one attempt to help... but it did

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what you are about to read is a copy paste of one attempt to help... but it did not work i got a message...'return' statement outside of function....i think the key is: use the variable i and the .length property to control the loop but i cant work it out.......................................................................................................................................... home / study / engineering / computer science / computer science questions and answers / The Incorrect Value 99 Was Found In Variable I (should Be 30) Your Code ( With Color Highlights ... Your question has been answered Let us know if you got a helpful answer. Rate this answer Question: The incorrect value 99 was found in variable i (should be 30) Your Code ( with color highlights a... the incorrect value 99 was found in variable i (should be 30) Your Code ( with color highlights added ): for (int j = 0; j < arraydata.lenght ; j++ ){ if (arraydata[j]==targetvar){ i = j + 1; } } The Instructions: Exercise 6.1 : O(N) Loop A classic O(N) algorithm is linear search, where every item is looked at until the target is found Write a 'for' loop to search the array of integers arraydata, use the variable i and the .length property to control the loop Use an 'if' statement to find a match for the value in the variable targetvar When the loop terminates i MUST contain the number of comparisons to find the value That number must be +1 of the slot the item was found in, if the item was found in slot zero, it took one comparison to find it Do not declare i or initialize arraydata or targetvar it will be done for you. Write only a loop with an if inside and remember when the value was found in slot 3 it took 3+1 or 4 comparisons to find it Expert Answer joker1234 answered this Was this answer helpful? 0 0 313 answers the incorrect value 99 was found in variable i (should be 30) Your Code ( with color highlights added ): for (int j = 0; j < arraydata.lenght ; j++ ){ if (arraydata[j]==targetvar){ i = j + 1; } } The problem with above code is that,when arraydata might contain multiple instance of targetvar above problem might occur.You want to terminate the loop when first match is found. for e.g arradata={1,4,3,6,4,8} assume targetvar=4 two 4's first at slot 1 second at slot 4 so if you execute your above code you will get i= j+1 = 4+1 =5 i.e comparisons of last match but we want to terminate at first match so use below code: Note: since questions only asks to write ONLY a loop and dont initialize and declare i,arraydata,targetvar ,i have answered as required. code: for (int j = 0; j < arraydata.lenght ; j++ ) { if (arraydata[j]==targetvar) { i=j+1; return i; //terminating the loop here since first match is found } }

Explanation / Answer

The error you are getting might be because of the reason that the function that you wrote to find out the no of comparisions requires an int to be returned to calling function but here in this case we are trying to return the int value only if it finds the match in the array. But what if the match is not found. After completion of the for loop your function have to return some integer value, since you couldn't find any match to the target value you are not returning anything.

So to avoid such errors we just need to keep a return statement just before closing the function body using the brackets '}'. So try to return value -1 if no target value is found.

This error will come since once we declare our function header with return type int, We have to use return statement before closing the fuction body. The return statement may or may not be executed but must be written to avoid syntax errors.

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