11. Function Tracing (20 points) Trace the following program. Show a work includ

Question

11. Function Tracing (20 points) Trace the following program. Show a work including labeled designated spaces. You should draw a box for each variable and show value updates. ll our work and the Show all of your boxes for user-defined functions, calculations, and the output in the #include using namespace std: void stewie(int, int &, int): void lois (int &, int, int &); void meg(int, int, int); int main( int numl 2, num2 4, num3 6, stewie (numl, num2, num3) meg (num3, numl, num2); lois (numl, num2, num3): meg (num3, numl, num2); system ("pause") return 0: void stewie(int a, int &b;, int c) int d; vanayl d=a+b+c; c=c+2; a=d%5; return; void lois(int su, int v, int w) u=u + v + w; Ww(v+1) meg (u, v, W) return; void meg(int x, int y, int z) cout

Explanation / Answer

At the starting of main..

num1=2

num2=4

num3=6

when function stewie is called

num1 and num3 are passed by value but num2 is passed by reference.

num1 and num3 are catched by a and c respectivly and num2 is referenced as b.

at this point of execution:

a=2

b=4

c=6

all remaining variables remain the same.

d=2+4+6=12

b=4%2=0

c=6+2=8

a=12%5=2

num2=b=0

After execution of stewie function:

a=2

b=0

c=8

d=12

num2=0

num1=2

num3=6

now when meg is called:

num3, num1, num2 are passed by value and catched by x,y,z repectively

x=6

y=2

z=0

they will be printed as.

6

2

0

at the end of this function all the other variables remain constant.

now when lois is called:

num1, num3 are passed by reference and are referenced by u,w repectively.

num2 is passed by value and catched by v.

u=2

v=0

w=6

now when the fun lois executes:

u=2+0+6=8

w=6/(0+1)=6

now when meg is called inside lois:

u,v,w are passed by value and catched by x,y,z repectively

x=8

y=0

z=6

they will be printed as.

8

0

6

at the end of meg function all the other variables remain constant.

at the end of lois function:

num1=u=8

num3=v=6

all the other variables remain constant.

now when meg is called again in main:

num3, num1, num2 are passed by value and catched by x,y,z repectively

x=num3=6

y=num1=8

z=num2=0

they will be printed

6

8

0.

at the end of this function all the other variables remain constant.

system("pause") pauses the execution until u hit enter

Output:

6

2

0

8

0

6

6

8

0

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