C Programming, Help with the homework Instructions: You are to turn in a text fi

Question

C Programming, Help with the homework

Instructions: You are to turn in a text file that includes all output from the program as well as all of the variable values at the requested locations
The code generated "should" all be valid, but if there are any lines that access arrays beyond their size, you are to correct the errors by
changing the invalid values to the maximum value that would be allowed.
So in other words, if x is a size 10 array and your homework includes the following line:
x[11] = 14;
you should change this to:
x[9] = 14;
And make a note in the document you turn in that you made this change.

Edit: No comments should be typed

Code:

#include
int func2(int a, int *b)
{
int c;
c = a;
a = *b + c;
printf("func2: %d %d %d ",a, *b, c);
return(c);
}

int func2_3(int *a, int b)
{
int c;
c = *a;
*a = b + c;
printf("func2_3: %d %d %d ",*a, b, c);
return(c);
}

int func2_34(int *a, int b)
{
int c;
c = *a;
a = &c;
*a = b + c;
printf("func2_34: %d %d %d ",*a, b, c);
return(c);
}

int main()
{
int *ptr, *a;
int b, c;
int d[10];

b = 10 + 7;
c = 10 + 2;
ptr = &b;
a = &b;
for (b = 0; b < 10; b += 1)
{
d[b] = b + 4;
}

//*ptr = ____
//*a = ____
//b = ____
//c = ____
//d = ____ ____ ____ ____ ____ ____ ____ ____ ____ ____

b = 4 + 10;
c = 3;
//*ptr = ____
//*a = ____
//b = ____
//c = ____
//d = ____ ____ ____ ____ ____ ____ ____ ____ ____ ____

for (c = 0; c < 10; c += 2)
{
printf("%d ",d[c]);
d[c + 1] = c / 2 + 9;
}

//*ptr = ____
//*a = ____
//b = ____
//c = ____
//d = ____ ____ ____ ____ ____ ____ ____ ____ ____ ____

a = &c;
for (c = 0; c < 10; c += 2)
{
printf("%d ",d[c]);
d[c + 1] = c / 2 + 9;
if (c % 4 == 0) { printf(" "); }
}

//*ptr = ____
//*a = ____
//b = ____
//c = ____
//d = ____ ____ ____ ____ ____ ____ ____ ____ ____ ____

ptr = &d[4];
a = &d[3];
for (*a = 1; *a < 4; *a += 1)
{
ptr[*a] = *a + 1;
printf("%d %d ", *a, ptr[*a]);
}

//*ptr = ____
//*a = ____
//b = ____
//c = ____
//d = ____ ____ ____ ____ ____ ____ ____ ____ ____ ____

printf("-- %d -- ", *d + 5);
printf("-- %d -- ", ptr[26 % 5] + 5);
func2(d[7], &d[4]);
//*ptr = ____
//*a = ____
//b = ____
//c = ____
//d = ____ ____ ____ ____ ____ ____ ____ ____ ____ ____

func2_3(&d[7], d[4]);
//*ptr = ____
//*a = ____
//b = ____
//c = ____
//d = ____ ____ ____ ____ ____ ____ ____ ____ ____ ____

func2_34(&d[7], d[4]);
//*ptr = ____
//*a = ____
//b = ____
//c = ____
//d = ____ ____ ____ ____ ____ ____ ____ ____ ____ ____

d[2] = func2(d[7], &d[4]);
//*ptr = ____
//*a = ____
//b = ____
//c = ____
//d = ____ ____ ____ ____ ____ ____ ____ ____ ____ ____

printf(" ");
return(0);
}

Explanation / Answer

Code:

#include<stdio.h>

int main()

{

int *ptr, *a;
int b, c;
int d[10];
b = 10 + 6;
c = 10 + 5;
ptr = &c;
a = &b;

for (b = 0; b < 10; b += 1)

{

d[b] = b + 6;
}

// *ptr=15   
//*a=10   
//b=10
//c=15
//d=1901419552

b = 4 + 9;
c = 2;

// *ptr=2
//*a=13   
//b=13
//c=2   
//d=1273426272   

for (c = 0; c < 10; c += 2)
{
printf(" d[%d] :%d ",c,d[c]);
d[c + 1] = c / 2 + 10;
}

// *ptr=10   
//*a=13   
//a=1888455836
//c=10
//d=1888455792
a = &c;
for (c = 0; c < 10; c += 2)
{
printf(" chk d[%d] %d ",c,d[c]);
d[c + 1] = c / 2 + 10;
if (c % 4 == 0) { printf(" "); }
}

// *ptr=10   
//*a=10   
//b=13
//c=10
//d=1412216864

ptr = &d[4];
a = &d[3];
for (*a = 1; *a < 4; *a += 1)
{
ptr[*a] = *a + 1;
printf(" a=%d ptr[%d] =%d ", *a,*a, ptr[*a]);
}

//*ptr=10   
//*a=4
//b=13
//c=10
//d=1288071072   

printf("-- %d -- ", *d + 7);
printf("-- %d -- ", ptr[27 % 5] + 7);
return 0;
}

If any queries please get back to me

Thank You

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