1) a) Design a program in C++ that models inflating a spherical balloon. First t

Question

1)

a) Design a program in C++ that models inflating a spherical balloon. First the balloon is inflated to have a certain diameter (which is provided as an input). Then inflate the balloon so that the diameter grows by an inch, and display the amount the volume has grown. Repeat that step: grow the diameter by another inch and show the growth of the volume. Hint: The volume of a sphere is 43 r3

Assuming that the input is 10, the two outputs, when rounded to the nearest integer will be 173 and 208

b) Rearrange the following lines of code to produce correct pseudocode for this task:

growth = volume2 - volume1

volume2 = × diameter × diameter × diameter / 6

Print growth

volume3 = × diameter × diameter × diameter / 6

volume1 = × diameter × diameter × diameter / 6

growth = volume3 - volume2

Prompt for diameter and read user input

Print growth

diameter++

diameter++

Explanation / Answer

#include <iostream>

using namespace std;

int main() {

double diameter;

cout << "Enter the diameter: ";

cin >> diameter;

int volume1 = 3.14 * diameter * diameter * diameter / 6;

diameter++;

int volume2 = 3.14 * diameter * diameter * diameter / 6;

diameter++;

int growth = volume2 - volume1;

cout << "Growth is " << growth << endl;

int volume3 = 3.14 * diameter * diameter * diameter / 6;

growth = volume3 - volume2;

cout << "Growth is " << growth << endl;

}

/*SAMPLE OUTPUT

Enter the diameter: 10

Growth is 173

Growth is 208

*/

/* Sequence of steps are given below

Prompt for diameter and read user input

volume1 = × diameter × diameter × diameter / 6
diameter++

volume2 = × diameter × diameter × diameter / 6
diameter++

growth = volume2 - volume1
Print growth

volume3 = × diameter × diameter × diameter / 6

growth = volume3 - volume2
Print growth

*/

// Hit the thumbs up if you are fine with the answer. Happy Learning!

#include <iostream>

using namespace std;

int main() {

double diameter;

cout << "Enter the diameter: ";

cin >> diameter;

int volume1 = 3.14 * diameter * diameter * diameter / 6;

diameter++;

int volume2 = 3.14 * diameter * diameter * diameter / 6;

diameter++;

int growth = volume2 - volume1;

cout << "Growth is " << growth << endl;

int volume3 = 3.14 * diameter * diameter * diameter / 6;

growth = volume3 - volume2;

cout << "Growth is " << growth << endl;

}

/*SAMPLE OUTPUT

Enter the diameter: 10

Growth is 173

Growth is 208

*/

/* Sequence of steps are given below

Prompt for diameter and read user input

volume1 = × diameter × diameter × diameter / 6
diameter++

volume2 = × diameter × diameter × diameter / 6
diameter++

growth = volume2 - volume1
Print growth

volume3 = × diameter × diameter × diameter / 6

growth = volume3 - volume2
Print growth

*/

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