The code is supposed to be in c++, I am having problems printing my results, so

Question

The code is supposed to be in c++, I am having problems printing my results, so I want to see how one of the experts would do it.

Some Background Hopefully you remember that a linear model is created by specifying a slope and an intercept where you can use the equation y-slope * x + intercept (y is the temp, x is the year). I gathered (see spreadsheet) the average global temp in degrees Fahrenheit, 1880-2012, and fit a linear model to it. The slope is 0.01173 degreesF/year and the intercept is 34.3491 degreesF. Using this information, you will write a program that does as follows. Program Specifications Your program will do the following: 1. Take as input two values: a. a year, as a long b. a slope, as a double 2. Print three results: Print the temperature for the year read in above based on the slope and intercept provided in the Background section. Print it as a double of precision 2. a. b. Print the year when, given the temperature calculated in a. above, a temperature 7 degrees greater will occur again using the slope and intercept provided in the Background. Print it as a rounded long. c. Print the year when, given the temperature calculated in a above, a temperature 7 degrees greater will occur using the second input, a new input slope, and the intercept provided in the Background. Print it as a rounded long.

Explanation / Answer

CODE :

#include <iostream>
#include <iomanip>

using namespace std;

int main()
{
    double m = 0.01173;     // slope
    double c = 34.3491;     // intercept
    long y;           // temperature
    double x;               // year
    cout << "Enter a year and a new slope." << endl;
    cin >> y;
    cin >> x;
    double temp = m*y + c;
    cout << fixed;
    cout << setprecision(2);    // fixes the number of digits to show after decimal
    cout << "Temperature : " << temp << endl;
    temp = temp + 7 - c;
    cout << setprecision(0);
    cout << "Year : " << (temp/m) << endl;
    cout << "Year : " << (temp/x) << endl;
    return 0;
}

*************NOTE*************
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