please solve the problem fully! thank you! 1.8 The Pentium 4 Prescott processor,

Question

please solve the problem fully! thank you!

1.8 The Pentium 4 Prescott processor, released in 2004, had a cdock rate of 3.6 GHz and voltage of 1.25 V. Assume that, on average, it consumed 10 w of static power and 90 W of dynamic power. The Core i5 Ivy Bridge, released in 2012, had a clock rate of 3.4 GHz and voltage of 0.9 V. Assume that, on average, it consumed 30 W of static power and 40 W of dynamic power 1.8.1 [5] For each processor find the average capacitive loads. 1.8.2 [5] Find the percentage of the total dissipated power comprised by static power and the ratio of static power to dynamic power for each technology. 1.8.3 [15]Ifthe total dissipated power is to be reduced by 10%, how much should the voltage be reduced to maintain the same leakage current? Note: power is defined as the product of voltage and current.

Explanation / Answer

1.8)

Given that

Pentium 4

clock rate =3.6ghz=3.6*109 hz 1ghz=109hz

voltage=1.25v

static power=10w

dynamic power=90w

Core i5

clock rate= 3.4 ghz =3.4* 109 hz

voltage=0.9v

static power=30w

dynamic power=40w

1.8.1)

Average Capactive Load= (2*power) /(clockrate * voltage2)

=(2 * 90) /(3.6 *109 * 1.252)=(180) /(3.6 * 109 *1.5625)

=(180) / (5.625 * 109)=32/109 =32*10-9

Average Capactive Load= (2*power) /(clockrate * voltage2)

=(2 * 40) /(3.4 *109 * 0.92)=(80) /(3.4 * 109 *0.81)

=(80) / (2.754 * 109)=29.04/109 =29.04*10-9

1.8.2) percentage of total power = static power/(static power+dynamic power)=10/10+90=10/100=10%

Ratio= static power /dynamic power =10/90 =1 :9

percentage of total power = static power/(static power+dynamic power)=30/30+40=30/70=43%

Ratio= static power /dynamic power =30/40=3:4

1.8.3)

Total dissipated power is reduced by 10%

static power / dynamic power=10/90=1/9

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